<?xml-stylesheet type="text/xsl" href="https://e2echina.ti.com/cfs-file/__key/system/syndication/rss.xsl" media="screen"?><rss version="2.0" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:slash="http://purl.org/rss/1.0/modules/slash/" xmlns:wfw="http://wellformedweb.org/CommentAPI/"><channel><title>猜猜看:运算放大器谜题</title><link>/blogs_/b/analogwire/posts/51623</link><description>作者： Tim Green1 
 
 放下严肃的技术文章形式，我来为大家出六道有关运算放大器的谜题，在公布正确答案之前，大家赶快来开动脑筋、享受一下思考的乐趣吧！ 
 
 我在图 1 中为您提供了一些有帮助的重要运算放大器规范。 
 
 
 
 
 参数 
 
 
 
 
 
 条件 
 
 
 OPA735 
 
 
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 最小值 
 
 
 典型值 
 
 
 最大值 
 
 
 
 
 
 </description><dc:language>zh-CN</dc:language><generator>Telligent Community 13</generator><item><title>回复:猜猜看:运算放大器谜题</title><link>https://e2echina.ti.com/blogs_/b/analogwire/posts/51623</link><pubDate>Sat, 01 Mar 2014 06:27:10 GMT</pubDate><guid isPermaLink="false">91561404-af28-475a-b96b-cb6cbaadd097:5509bc1d-e9b8-4860-8875-e34329307b1a</guid><dc:creator>11 12</dc:creator><slash:comments>0</slash:comments><description>&lt;p&gt;第三题3.85V，第四题4V,第六题3.85V&lt;/p&gt;
&lt;img src="https://e2echina.ti.com/aggbug?PostID=51623&amp;AppID=102&amp;AppType=Weblog&amp;ContentType=0" width="1" height="1"&gt;</description></item><item><title>回复:猜猜看:运算放大器谜题</title><link>https://e2echina.ti.com/blogs_/b/analogwire/posts/51623</link><pubDate>Mon, 24 Feb 2014 04:45:06 GMT</pubDate><guid isPermaLink="false">91561404-af28-475a-b96b-cb6cbaadd097:5509bc1d-e9b8-4860-8875-e34329307b1a</guid><dc:creator>Mark Lee</dc:creator><slash:comments>0</slash:comments><description>&lt;p&gt;正确答案：&lt;/p&gt;
&lt;p&gt;2.97v&lt;/p&gt;
&lt;p&gt;-4v&lt;/p&gt;
&lt;p&gt;3.52v&lt;/p&gt;
&lt;p&gt;3.5v&lt;/p&gt;
&lt;p&gt;floating voltage&lt;/p&gt;
&lt;p&gt;3.85v&lt;/p&gt;
&lt;img src="https://e2echina.ti.com/aggbug?PostID=51623&amp;AppID=102&amp;AppType=Weblog&amp;ContentType=0" width="1" height="1"&gt;</description></item><item><title>回复:猜猜看:运算放大器谜题</title><link>https://e2echina.ti.com/blogs_/b/analogwire/posts/51623</link><pubDate>Fri, 21 Feb 2014 09:04:16 GMT</pubDate><guid isPermaLink="false">91561404-af28-475a-b96b-cb6cbaadd097:5509bc1d-e9b8-4860-8875-e34329307b1a</guid><dc:creator>Mark Lee</dc:creator><slash:comments>0</slash:comments><description>&lt;p&gt;失调很小啊，否则就得考虑失调对增益后输出的影响了。运放内阻大约50欧姆。&lt;/p&gt;
&lt;p&gt;-3v；-4v；3.85v；4v；1v；4v&lt;/p&gt;
&lt;img src="https://e2echina.ti.com/aggbug?PostID=51623&amp;AppID=102&amp;AppType=Weblog&amp;ContentType=0" width="1" height="1"&gt;</description></item><item><title>回复:猜猜看:运算放大器谜题</title><link>https://e2echina.ti.com/blogs_/b/analogwire/posts/51623</link><pubDate>Thu, 20 Feb 2014 13:47:40 GMT</pubDate><guid isPermaLink="false">91561404-af28-475a-b96b-cb6cbaadd097:5509bc1d-e9b8-4860-8875-e34329307b1a</guid><dc:creator>mangui zhang</dc:creator><slash:comments>0</slash:comments><description>&lt;p&gt;这些参数确实关注少了 &amp;nbsp; &amp;nbsp;模电基础太差啦&lt;/p&gt;
&lt;img src="https://e2echina.ti.com/aggbug?PostID=51623&amp;AppID=102&amp;AppType=Weblog&amp;ContentType=0" width="1" height="1"&gt;</description></item><item><title>回复:猜猜看:运算放大器谜题</title><link>https://e2echina.ti.com/blogs_/b/analogwire/posts/51623</link><pubDate>Thu, 20 Feb 2014 09:48:15 GMT</pubDate><guid isPermaLink="false">91561404-af28-475a-b96b-cb6cbaadd097:5509bc1d-e9b8-4860-8875-e34329307b1a</guid><dc:creator>Zhang Haifei</dc:creator><slash:comments>0</slash:comments><description>&lt;p&gt;回家用电脑看看&lt;/p&gt;
&lt;img src="https://e2echina.ti.com/aggbug?PostID=51623&amp;AppID=102&amp;AppType=Weblog&amp;ContentType=0" width="1" height="1"&gt;</description></item><item><title>回复:猜猜看:运算放大器谜题</title><link>https://e2echina.ti.com/blogs_/b/analogwire/posts/51623</link><pubDate>Thu, 20 Feb 2014 09:12:23 GMT</pubDate><guid isPermaLink="false">91561404-af28-475a-b96b-cb6cbaadd097:5509bc1d-e9b8-4860-8875-e34329307b1a</guid><dc:creator>gaoyang9992006</dc:creator><slash:comments>0</slash:comments><description>&lt;p&gt;第六题是3V？？？VIN 1表示参考电压是1V吗？&lt;/p&gt;
&lt;img src="https://e2echina.ti.com/aggbug?PostID=51623&amp;AppID=102&amp;AppType=Weblog&amp;ContentType=0" width="1" height="1"&gt;</description></item></channel></rss>