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fft_sp_1d_r2c 列子中怎么 测 DSPF_sp_fftSPxSP函数执行时间？？

user5329195
Intellectual 270 points
Other Parts Discussed in Thread: FFTLIB

我用fft_sp_1d_r2c这个例子，想评估FFTLIB库中fft_sp_1d_r2c这个fft函数中ecpy fft模式和 direct fft模式 性能同时也能和DSPLIB库中DSPF_sp_fftSPxSP函数性能做对比，我该怎么加记录时间？

如图


下面是我自己添加的 请大神帮忙确认是否正确？


 

 

  • 0
    TI__Guru**** 357097 points
    为什么还要减t_overhead？
  • 0 回复 Shine
    Intellectual 270 points
    我是参考了ecpy 模式和 direct模式 计算时间时都减了t_overhead
    其实我对这个t_overhead 还有些不明白，有没有想象介绍的？
  • 0 回复 Shine
    Intellectual 270 points

    [TMS320C66x_0] N = 16384 DSPF_sp_fftSPxSP Cycle: 151780

    FFT memory buffers:
    Buffer Size(bytes) Alignment
    0 131072 3
    1 131072 3
    2 1032 3
    3 0 3
    4 4096 3
    5 4096 3
    6 1032 3
    7 0 3
    8 0 3
    9 2048 3
    fft_sp_1d_c2c_ecpy size= 16384
    max_diff = 0.017578 N = 16384 Cycle: 1609576

    FFT memory buffers:
    Buffer Size(bytes) Alignment
    0 131072 3
    1 131072 3
    2 8 3
    3 0 3
    4 0 3
    5 0 3
    6 0 3
    7 0 3
    8 0 3
    9 0 3
    fft_sp_1d_c2c_direct size= 16384
    max_diff = 6.367188 N = 16384 Cycle: 152897

    N = 32768 DSPF_sp_fftSPxSP Cycle: 348407

    FFT memory buffers:
    Buffer Size(bytes) Alignment
    0 262144 3
    1 262144 3
    2 1032 3
    3 0 3
    4 8192 3
    5 8192 3
    6 1032 3
    7 0 3
    8 0 3
    9 4096 3
    fft_sp_1d_c2c_ecpy size= 32768
    max_diff = 0.032227 N = 32768 Cycle: 3061928

    FFT memory buffers:
    Buffer Size(bytes) Alignment
    0 262144 3
    1 262144 3
    2 8 3
    3 0 3
    4 0 3
    5 0 3
    6 0 3
    7 0 3
    8 0 3
    9 0 3
    fft_sp_1d_c2c_direct size= 32768
    max_diff = 14.457031 N = 32768 Cycle: 338085

    N = 65536 DSPF_sp_fftSPxSP Cycle: 696576

    FFT memory buffers:
    Buffer Size(bytes) Alignment
    0 524288 3
    1 524288 3
    2 2056 3
    3 0 3
    4 8192 3
    5 8192 3
    6 2056 3
    7 0 3
    8 0 3
    9 4096 3
    fft_sp_1d_c2c_ecpy size= 65536
    max_diff = 0.164063 N = 65536 Cycle: 5912488

    FFT memory buffers:
    Buffer Size(bytes) Alignment
    0 524288 3
    1 524288 3
    2 8 3
    3 0 3
    4 0 3
    5 0 3
    6 0 3
    7 0 3
    8 0 3
    9 0 3
    fft_sp_1d_c2c_direct size= 65536
    max_diff = 32.437500 N = 65536 Cycle: 741153

     

    为什么同样size的数据

    DSPF_sp_fftSPxSP函数执行时间比

     fft_sp_1d_r2c还要少？？？

  • 0 回复 Shine
    Intellectual 270 points

    下面是我的代码