Dear all：
在使用epwm触发ADC时，使用ADCA1配置为ADCINT1中断，程序可以正常运行，相关程序如下程序如下：
EALLOW;
PieVectTable.ADCA1_INT = &adcA1ISR; // Function for ADCA interrupt 1
EDIS;
IER |= M_INT1;//T0 ADCINT1
PieCtrlRegs.PIEIER1.bit.INTx1 = 1;// ADCINT1
EPwm1Regs.ETSEL.bit.SOCAEN = 0; // Disable SOC on A group
EPwm1Regs.ETSEL.bit.SOCASEL = 3; // Select SOC on up-count
EPwm1Regs.ETPS.bit.SOCAPRD = 1; // Generate pulse on 1st event
EPwm1Regs.CMPA.bit.CMPA = 430; // Set compare A value to 2048 counts
EPwm1Regs.TBPRD = 862; // Set period to 4096 counts
EPwm1Regs.TBCTL.bit.CTRMODE = 3; // Freeze counter
AdcaRegs.ADCSOC0CTL.bit.CHSEL = 7; // SOC0 will convert pin A1
// 0:A0 1:A1 2:A2 3:A3
// 4:A4 5:A5 6:A6 7:A7
// 8:A8 9:A9 A:A10 B:A11
// C:A12 D:A13 E:A14 F:A15
AdcaRegs.ADCSOC0CTL.bit.ACQPS = 9; // Sample window is 10 SYSCLK cycles
AdcaRegs.ADCSOC0CTL.bit.TRIGSEL = 5; // Trigger on ePWM1 SOCA
AdcaRegs.ADCINTSEL1N2.bit.INT1SEL = 0; // End of SOC0 will set INT1 flag
AdcaRegs.ADCINTSEL1N2.bit.INT1E = 1; // Enable INT1 flag
AdcaRegs.ADCINTSEL1N2.bit.INT1CONT = 0; //不连续
AdcaRegs.ADCINTFLGCLR.bit.ADCINT1 = 1; // Make sure INT1 flag is cleared
__interrupt void adcA1ISR(void)
{
LED_FLASH=1;
Current.Sum+=AdcaResultRegs.ADCRESULT0;
if(++Current.ConversionCount==80)
{
Current.ConversionCount=0;
Current.Data=(Current.Sum/80);
Current.Sum=0;
EALLOW;
EPwm1Regs.ETSEL.bit.SOCAEN = 0; // Enable SOC on A group
EPwm1Regs.TBCTL.bit.CTRMODE = 3; // Unfreeze, and enter up count mode
EDIS;
}
//
// Clear the interrupt flag
//
AdcaRegs.ADCINTFLGCLR.bit.ADCINT1 = 1;
//
// Check if overflow has occurred
//
if(1 == AdcaRegs.ADCINTOVF.bit.ADCINT1)
{
AdcaRegs.ADCINTOVFCLR.bit.ADCINT1 = 1; //clear INT1 overflow flag
AdcaRegs.ADCINTFLGCLR.bit.ADCINT1 = 1; //clear INT1 flag
}
//
// Acknowledge the interrupt
//
PieCtrlRegs.PIEACK.all = PIEACK_GROUP1;
}
上面测试代码中在定时中使能ePWM 开启
EPwm1Regs.ETSEL.bit.SOCAEN = 1; // Enable SOC on A group
EPwm1Regs.TBCTL.bit.CTRMODE = 0; // Unfreeze, and enter up count mode
转换80个周期，每个周期时间是17.2us, 使用 LED_FLASH=1; 测试管脚来查看转换的周期和每个周期的个位。
上述程序运行正常。
但是ADCINT1已经被其他功能占用，配置到ADCINT2 中断上，使用发现就不能正常运行，相关程序如下：EALLOW;
PieVectTable.ADCA2_INT = &adcA2ISR; // Function for ADCA interrupt 2
EDIS;
IER |= M_INT10; //ADCINT2
PieCtrlRegs.PIEIER10.bit.INTx2 = 1;// ADCINT2
EPwm1Regs.ETSEL.bit.SOCAEN = 0; // Disable SOC on A group
EPwm1Regs.ETSEL.bit.SOCASEL = 3; // Select SOC on up-count
EPwm1Regs.ETPS.bit.SOCAPRD = 1; // Generate pulse on 1st event
EPwm1Regs.CMPA.bit.CMPA = 430; // Set compare A value to 2048 counts
EPwm1Regs.TBPRD = 862; // Set period to 4096 counts
EPwm1Regs.TBCTL.bit.CTRMODE = 3; // Freeze counter
AdcaRegs.ADCSOC1CTL.bit.CHSEL = 7; // SOC1 will convert pin A1
// 0:A0 1:A1 2:A2 3:A3
// 4:A4 5:A5 6:A6 7:A7
// 8:A8 9:A9 A:A10 B:A11
// C:A12 D:A13 E:A14 F:A15
AdcaRegs.ADCSOC1CTL.bit.ACQPS = 9; // Sample window is 10 SYSCLK cycles
AdcaRegs.ADCSOC1CTL.bit.TRIGSEL = 5; // Trigger on ePWM1 SOCA
AdcaRegs.ADCINTSEL1N2.bit.INT2SEL = 1; // End of SOC0 will set INT2 flag
AdcaRegs.ADCINTSEL1N2.bit.INT2E = 1; // Enable INT2 flag
AdcaRegs.ADCINTSEL1N2.bit.INT2CONT = 0; //不连续
AdcaRegs.ADCINTFLGCLR.bit.ADCINT2 = 1; // Make sure INT2 flag is cleared
__interrupt void adcA2ISR(void)
{
LED_FLASH=1;
Current.Sum+=AdcaResultRegs.ADCRESULT1;
if(++Current.ConversionCount==80)
{
Current.ConversionCount=0;
Current.Data=(Current.Sum/80);
Current.Sum=0;
EALLOW;
EPwm1Regs.ETSEL.bit.SOCAEN = 0; // Enable SOC on A group
EPwm1Regs.TBCTL.bit.CTRMODE = 3; // Unfreeze, and enter up count mode
EDIS;
}
//
// Clear the interrupt flag
//
AdcaRegs.ADCINTFLGCLR.bit.ADCINT2 = 1;
//
// Check if overflow has occurred
//
if(1 == AdcaRegs.ADCINTOVF.bit.ADCINT2)
{
AdcaRegs.ADCINTOVFCLR.bit.ADCINT2 = 1; //clear INT2 overflow flag
AdcaRegs.ADCINTFLGCLR.bit.ADCINT2 = 1; //clear INT2 flag
}
//
// Acknowledge the interrupt
//
PieCtrlRegs.PIEACK.all = PIEACK_GROUP1;
}
通过示波器测试LED_FLASH=1; 管脚上的电平转换时间是20ms,运行不正常
也没查找出是什么具体原因。
原来之前使用的是28065也是这么使用，可以正常工作，插入一段28065的程序
PieVectTable.ADCINT1 = &adc_isr; // ADC Signal
PieVectTable.ADCINT2 = &adc_current_isr; // ADC current
IER |= M_INT1; // T0 ADCINT1
PieCtrlRegs.PIEIER1.bit.INTx1 = 1; // ADCINT1 P1.1
PieCtrlRegs.PIEIER1.bit.INTx2 = 1; // ADCINT2
EALLOW;
AdcRegs.ADCCTL1.bit.ADCREFSEL = 1; //外部电源参考
AdcRegs.ADCCTL1.bit.INTPULSEPOS = 1; //结果存入寄存器才产生中断
AdcRegs.ADCSAMPLEMODE.bit.SIMULEN0 = 1; //同时采样
AdcRegs.ADCSOC0CTL.bit.CHSEL = 0; //soc通道选择
// AdcRegs.ADCSOC1CTL.bit.CHSEL = 8;
AdcRegs.ADCSOC0CTL.bit.ACQPS = 25; //采样时间 25
AdcRegs.ADCSOC1CTL.bit.ACQPS = 25;
AdcRegs.ADCSOC0CTL.bit.TRIGSEL = 1; //
AdcRegs.ADCSAMPLEMODE.bit.SIMULEN2 = 1; //同时采样
AdcRegs.ADCSOC2CTL.bit.CHSEL = 1; //soc通道选择
// AdcRegs.ADCSOC3CTL.bit.CHSEL = 9;
AdcRegs.ADCSOC2CTL.bit.ACQPS = 50; //采样时间 20
AdcRegs.ADCSOC3CTL.bit.ACQPS = 50;
AdcRegs.ADCSOC2CTL.bit.TRIGSEL = 5; //set SOC2 start trigger on EPWM1A, due to round-robin SOC2 converts first then SOC3
// AdcRegs.ADCSOC3CTL.bit.TRIGSEL = 5; //set SOC3 start trigger on EPWM1A, due to round-robin SOC2 converts first then SOC3
//EPwm1Regs.ETSEL.bit.SOCAEN = 1; // Enable SOC on A group
EPwm1Regs.ETSEL.bit.SOCASEL = 3; // Enable event time-base counter equal to zero or period
EPwm1Regs.ETPS.bit.SOCAPRD = 1; // Generate pulse on 1st event
AdcRegs.INTSEL1N2.bit.INT2SEL = 2; //中断线2选择soc3
AdcRegs.INTSEL1N2.bit.INT2CONT = 0; //不连续
AdcRegs.INTSEL1N2.bit.INT2E = 1; //中断使能
AdcRegs.INTSEL1N2.bit.INT1SEL = 1; //中断线1选择soc1
AdcRegs.INTSEL1N2.bit.INT1CONT = 0; //不连续
AdcRegs.INTSEL1N2.bit.INT1E = 1; //中断使能
EDIS;
28065 ADCINT1和ADCINT2都能正常运行。
请大家帮忙分析280021 上如何正常使用ADCINT2，（ADCINT1已经被占用），并且必须是在PWM触发上去ADC中断。
