DRV2605L: DRV2605L LRA驱动

Do you have reference mean/avg driving current of DRV2605 to drive a normal LRA part?

It is difficult to provide such a spec due to variation in impedance and rated voltage of any one acctuator. this could however be estimated for any particular LRA. you can estimate the power based on the RMS rated voltage of the LRA and that LRAs impedance.

for example 3V RMS into an 16 Ohm LRA: 3^2/16 = 0.5625 W

Hope this is helpful.

Noted, thank you. I will wait for your further feedback. On the other hand, how can I get or buy 20 pcs of DRV2605LTDGSRQ1's samples? How about rough L/T?

Gary Xu 说：

Thank you.On the other hand, could you kindly help to check if the following hardware application schematic is OK for  DRV2605LTDGSRQ1 to driver LRA?

I2C will be connected to host MCU. VCC1 is 3.3V DC.

The schematic of the LRA driver you attached is good. We would recommend you to ensure the REG, and VDD capacitors are placed close to the device pin.

the additional 10 uf on VDD is not necessary, however it will not affect performance.

Gary Xu 说：

how can I get or buy 20 pcs of DRV2605LTDGSRQ1's samples? How about rough L/T?

For the new question I will update to the engineer. 

Hello may I ask that?:

if input VDD is 5V, what's RMS voltage for OUT+ OUT-? If input VDD is 3.3V, what's RMS voltage for OUT+ OUT-?

Thank you.

Hi dear, 

Thanks for you feedback. We have ask the other team's help for your issue. Please expect the response.

Best Regards,

Cherry