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信号频率1k，幅值1v到3v，放大100倍，发现失真，才1k的频率，供电是正负5v，请问为什么呢
放大后输出1v到3v
是不是跟压摆率有关，能解释下这个图吗？
SR=2*PAI*f*Vp,放大后输出1V到3V的幅值,那么Vpp=2V, Vp=1V.
所以带入之后计算SR=6.28V/ms=0.00628V/us.所以压摆率是够的.
麻烦附上电路和失真波形看下.
