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sn74avc8t245问题

miao meng
Prodigy 130 points
Other Parts Discussed in Thread: SN74AVC8T245

Hi,

I am using sn74avc8t245 as voltage shifter from 0~3.3 V to 0~2.4 V, I have three questions regarding this part:

1. How should I connect the pins (i.e VCCA, Two VCCB, DIR, OE)

2. What does continuous output current mean (under absolute maximum ratings on page 3)? What is the difference between continuous output current and IOH/IOL?

3. Is this part able to drive a 50 Ohm resistor? If not, do you know any part can drive 50 Ohms with a voltage level of 0~2.4?

Many thanks in advance!

Miao

  • 0
    Guru 34090 points

    Hi,

    1.VCCA and VCCB are the two supply voltage for voltage level switch.DIR controls the direction between VCCA and VCCB,OE is the enable pin.

    2.Continuous output current is relative to the pulse current,IOH High-level output current,IOL Low-level output current;

    3.most of the time it is not used to drive a load,but used for BUS TRANSCEIVER.

    Carter