你好,我想问下28035 80PIN与64PIN,56PIN的功耗是不是会大点?因为引脚比较多
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你好,我想问下28035 80PIN与64PIN,56PIN的功耗是不是会大点?因为引脚比较多
这里可以关闭你不用的,降低你的功耗
SysCtrlRegs.PCLKCR0.bit.ADCENCLK = 1; // ADC
SysCtrlRegs.PCLKCR3.bit.COMP1ENCLK = 1; // COMP1
SysCtrlRegs.PCLKCR3.bit.COMP2ENCLK = 1; // COMP2
SysCtrlRegs.PCLKCR3.bit.COMP3ENCLK = 1; // COMP3
SysCtrlRegs.PCLKCR1.bit.ECAP1ENCLK = 0; // eCAP1
SysCtrlRegs.PCLKCR0.bit.ECANAENCLK = 1; // eCAN-A
SysCtrlRegs.PCLKCR1.bit.EQEP1ENCLK = 0; // eQEP1
SysCtrlRegs.PCLKCR1.bit.EPWM1ENCLK = 1; // ePWM1
SysCtrlRegs.PCLKCR1.bit.EPWM2ENCLK = 1; // ePWM2
SysCtrlRegs.PCLKCR1.bit.EPWM3ENCLK = 1; // ePWM3
SysCtrlRegs.PCLKCR1.bit.EPWM4ENCLK = 1; // ePWM4
SysCtrlRegs.PCLKCR1.bit.EPWM5ENCLK = 1; // ePWM5
SysCtrlRegs.PCLKCR1.bit.EPWM6ENCLK = 1; // ePWM6
SysCtrlRegs.PCLKCR1.bit.EPWM7ENCLK = 1; // ePWM7
SysCtrlRegs.PCLKCR0.bit.HRPWMENCLK = 0; // HRPWM
SysCtrlRegs.PCLKCR0.bit.I2CAENCLK = 0; // I2C
SysCtrlRegs.PCLKCR0.bit.LINAENCLK = 0; // LIN-A
SysCtrlRegs.PCLKCR3.bit.CLA1ENCLK = 1; // CLA1
SysCtrlRegs.PCLKCR0.bit.SCIAENCLK = 1; // SCI-A
SysCtrlRegs.PCLKCR0.bit.SPIAENCLK = 1; // SPI-A
SysCtrlRegs.PCLKCR0.bit.SPIBENCLK = 1; // SPI-B
SysCtrlRegs.PCLKCR2.bit.HRCAP1ENCLK = 0;
SysCtrlRegs.PCLKCR2.bit.HRCAP2ENCLK = 0;