适配器15V 2A,最小输入电压11.2V,充电电流1.35A,4s电池16.8V。
充电过程中概率性停止充电,停止充电瞬间读取寄存器值如下,可以看到进入VINDPM模式,输入电压回读为11.1V。
请问:
1、BQ25720是什么原因导致无输出(此时系统电压是电池提供,断开电池整机断电,判断BQ25720无输出)?
2、有什么办法可以避免触发该事件
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适配器15V 2A,最小输入电压11.2V,充电电流1.35A,4s电池16.8V。
充电过程中概率性停止充电,停止充电瞬间读取寄存器值如下,可以看到进入VINDPM模式,输入电压回读为11.1V。
请问:
1、BQ25720是什么原因导致无输出(此时系统电压是电池提供,断开电池整机断电,判断BQ25720无输出)?
2、有什么办法可以避免触发该事件
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HI Tiger
1、 This is when charging normally,why STAT_VDPM was sitll triggered.status=2,TSHUT=0,Proc=0xB880,chg_curr=640,dsg_curr=0,vbus_volt=15168,vbat_volt=11136,vsys_volt=11200,ibus_curr=1850
[0x12]:0x070E,[0x14]:0x0540,[0x15]:0x41A0,[0x3B]:0x09C4,[0x3C]:0x3C00,[0x3D]:0x1F40,[0x3E]:0x7100,[0x3F]:0x2800,
[0x20]:0x8C00,[0x21]:0xB880,[0x22]:0x2800,[0x23]:0x9E00,[0x24]:0x0A00,[0x25]:0x2500,[0x26]:0xAFAE,[0xFE]:0x0040,
[0xFF]:0x00E1,[0x30]:0x3300,[0x31]:0x00B7,[0x32]:0x0434,[0x33]:0x4A81,[0x34]:0x41A0,[0x35]:0xB0FF,[0x36]:0x0048,
2、 Is it because the minimum input voltage setting is too high(11.2V) that the VINDPM mode is entered。Can it be set to 3.2V?
您好,请参考下面内容
when VBUS exceeds VVBUS_UVLOZ or VBAT exceeds VVBAT_UVLOZ. 5 ms after either VBUS or VBAT becomes valid, the charger resets all the registers to the default state. Another 5 ms later, the user registers become accessible to the host.