如何根据规格书给出的数据表来计算这个电流的采集误差呢?
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More information can be found in sections 5.4 and 5.5 of the FAQ document: bq76920, bq76930, bq76940 AFE FAQ (Rev. A) (ti.com).
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Assuming we ignore non-linearity and offset. The current error would be determined by the gain error.
Datasheet gives a worst-case gain error of 1.5% of the full scale range of the coulomb counter. the full range is -270-mV to 270-mV. So, 1.5% of this range would correspond to ~4-mV of gain error across the whole range. This would be the error at the edges of the voltage range of the coulomb counter, so at ~270-mV.
Let's assume that there is a 2000-mA current flowing through, if we assume the worst gain error is 1.5%, this means that the measurement could be read as 2030-mA. Although this depends on the sense resistor used. The current error due to gain will never be more than 1.5%.
Offset and INL errors are given with respect to LSB's. Which is given as 8.44-uV per LSB.