ACF2101: Why does the ACF2101output +0.5 voltage?（为什么ACF2101能够输出+0.5电压？）

Yue Li

Part Number: ACF2101

The datasheet mentions that the integrator output voltage range is from +0.5V to –10V. As charge accumulates, the voltage across the integration capacitor rises, and the output voltage of the ACF2101 gradually decreases from 0V to a minimum of -10V. So, under what circumstances would it output a positive voltage?
(ACF2101数据手册中提到积分器输出电压范围为+0.5V至-10V。随着电荷的积累，积分电容两端的电压升高，ACF2101的输出电压从0V逐渐降低到最低-10V。那么，在什么情况下它会输出正电压呢？）

4 天前

0 Vivian Gao 17 小时前

TI__Mastermind 39140 points

I believe the output range specification is to explain the output swing range the device is capable of. So the device is able to swing from -10V to +0.5V min and max respectively but typically can swing to -13.5V to +1.0V.

As outlined in the transfer function, the device will output a negative voltage from 0 to -10V, shown in the typical applications in the datasheet.

There is not a specific circumstance that the device is going to output a positive voltage. In most application use cases, the device will be outputting a negative voltage.

Please let me know if there are further questions.

0 Yue Li 15 小时前回复 Vivian Gao

Prodigy 10 points

I am using the ACF2101 chip to perform photodiode output current-to-voltage conversion. The circuit design is shown in the figure, with the S1336-8BQ photodiode's anode connected to the SWIN pin of the ACF2101.
When there is no light, the output of the ACF2101 is +380mV. How should I interpret this phenomenon? Additionally, could you help verify if the placement of the photodiode in the circuit design is correct?

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ACF2101: Why does the ACF2101output +0.5 voltage?（为什么ACF2101能够输出+0.5电压？）