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在文献中提到：该电路具有两个真实的电极，它们决定高通滤波器的 –3dB 频率。将它们都设置为 fL /1.557，从而在截止频率下限 (fL ) 上得到 –3dB。
为什么需要设置fL/1.557，才能得到-3db处的频率是fL?这个1.557是怎么来的？
您好，
下面帖子中有解释：
https://e2e.ti.com/support/amplifiers-group/amplifiers/f/amplifiers-forum/959702/ac-coupled-hpf-non-inverting-amplifier-circuit?tisearch=e2e-sitesearch&keymatch=AC%25252520coupled%25252520%25252528HPF%25252529%25252520non-inverting%25252520amplifier%25252520circuit#
完美的解答了我的问题，非常感谢！
不客气
