您好,我在参考snou004 LMP7721 Multi-Function Evaluation Board Users' Guide这个参考设计时,Transimpedance Configuration这个配置下,输出电压的公式为Vout = -I / RF (第7页)
1.这个公式怎么理解,TIA的输出计算不应该是VOUT=-I*RF嘛?
2.如果按照公式Vout = -I / RF,那么反馈电阻RF变大,VOUT输出不就变小了嘛?
祝好!
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您好,我在参考snou004 LMP7721 Multi-Function Evaluation Board Users' Guide这个参考设计时,Transimpedance Configuration这个配置下,输出电压的公式为Vout = -I / RF (第7页)
1.这个公式怎么理解,TIA的输出计算不应该是VOUT=-I*RF嘛?
2.如果按照公式Vout = -I / RF,那么反馈电阻RF变大,VOUT输出不就变小了嘛?
祝好!
您好,这里应该是打印错误,您的理解是正确的,跨阻运放输出电压Vout=-I*Rf 。