Other Parts Discussed in Thread: ADC08D1500
设计使用LMH6555匹配ADC08D1500, 单端输入0.34Vpp,计算为(0.34/2)*4.83=0.820Vpp, 差分输出内部有RT1/RT2 50ohm,那么ADC08D1500 采集到的幅度为0.82Vpp/2=0.41Vpp,对吧?
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设计使用LMH6555匹配ADC08D1500, 单端输入0.34Vpp,计算为(0.34/2)*4.83=0.820Vpp, 差分输出内部有RT1/RT2 50ohm,那么ADC08D1500 采集到的幅度为0.82Vpp/2=0.41Vpp,对吧?