[参考译文] CC2652R7：同时捕获脉冲、但丢弃一个脉冲中断。

您好 Kenneth、

您是否能够提供一个基本代码文件来演示您的 GPTimer 设置、并能帮助我们重现您所描述的问题？  是否调用了同一个 GPTimer 中断、或者两者之间是否不同？  如果其中一个被禁用、那么另一个中断是否始终被处理？  如果使用3.3V 电源电平、是否会发生相同的行为？

您是否正在使用 TI 驱动程序、 driverlib或 直接访问硬件寄存器？  您可以通过调试计时器的寄存器中断状态来收集哪些信息？  此外、您正在评估哪个版本的 F2 SDK？

此致、
Ryan

vector<GPTimerCC26XX_Handle> gptimer_handles(2);
for (size_t t = 0; t < 2; t++) 
{ 
    // Configure GPTimer for edge time capture
    GPTimerCC26XX_Params gptimer_params;
    GPTimerCC26XX_Params_init(&gptimer_params);
    gptimer_params.width          = GPT_CONFIG_16BIT;
    gptimer_params.mode           = GPT_MODE_EDGE_TIME;
    gptimer_params.matchTiming    = GPTimerCC26XX_SET_MATCH_NEXT_CLOCK;
    gptimer_params.direction      = GPTimerCC26XX_DIRECTION_UP;
    gptimer_params.debugStallMode = GPTimerCC26XX_DEBUG_STALL_OFF;

    // Open GPTimer and set argument to "this" object for callback to use
    GPTimerCC26XX_Handle gptimer_handle = GPTimerCC26XX_open(t, &gptimer_params);
    gptimer_handles[t] = gptimer_handle;
    GPTimerCC26XX_setArg(gptimer_handle, this);

    // Configure Gpio for edge interrupt
    if (t == 0)
    {
        gpio.configure(Gpio::PinId::DIO_16, Gpio::Direction::INPUT, Gpio::Pull::NONE, Gpio::State::NONE, Gpio::Strength::NONE, GPTimerCC26XX_getPinMux(gptimer_handle));
    }
    else if (t == 1)
    {
        gpio.configure(Gpio::PinId::DIO_1, Gpio::Direction::INPUT, Gpio::Pull::NONE, Gpio::State::NONE, Gpio::Strength::NONE, GPTimerCC26XX_getPinMux(gptimer_handle));
    }

    // Set load value in order to support full/max 24-bit capability, configure edge mode and register callback
    GPTimerCC26XX_setLoadValue(gptimer_handle, MAX_GPTIMER_COUNT);
    GPTimerCC26XX_setCaptureEdge(gptimer_handle,
                                 both_edges ? GPTimerCC26XX_BOTH_EDGES : (rising_edge ? GPTimerCC26XX_POS_EDGE : GPTimerCC26XX_NEG_EDGE));
    GPTimerCC26XX_registerInterrupt(gptimer_handle, gptimerCallback, GPT_INT_CAPTURE);
    GPTimerCC26XX_start(gptimer_handle); 
} 

tx_gpio.writeHigh(); 

for (size_t t = 0; t < 2; t++) 
{ 
    first_edge_sem.wait(); 
} 

for (size_t t = 0; t < 2; t++) 
{ 
    _second_edge_sem.wait(); 
} 

tx_gpio.writeLow();

for (size_t t = 0; t < 2; t++) 
{ 
    // Stop and close GPTimer
    GPTimerCC26XX_unregisterInterrupt(gptimer_handles[t]);
    GPTimerCC26XX_stop(gptimer_handles[t]);
    GPTimerCC26XX_close(gptimer_handles[t]);
} 

void Timer::gptimerCallback(GPTimerCC26XX_Handle gptimer_handle, GPTimerCC26XX_IntMask interruptMask)
{
    // Capture edge value
    Timer* timer = reinterpret_cast<Timer*>(GPTimerCC26XX_getArg(gptimer_handle));
    if (timer->_edge_count == 0)
    {
        timer->_first_edge_gpt = GPTimerCC26XX_getValue(gptimer_handle);
        timer->_first_edge_sem.post();
    }
    else if (timer->_edge_count == 1)
    {
        timer->_second_edge_gpt = GPTimerCC26XX_getValue(gptimer_handle);
        timer->_second_edge_sem.post();
    }
    timer->_edge_count++;
}

尊敬的 Kenneth：

感谢您提供这些详细信息。  我需要一段时间来找到复制和调试此行为的时间。  作为 额外的调试信息、 是否是始终被调用的同一 GPTimer 中断(即另一个中断始终被忽略)、这是哪一个？   如果对每个 GPTimer 使用单独的回调(gptimerCallback)、问题是否会得到缓解？

此致、
Ryan

嗨、Ryan、

看起来两个中断都在产生、但其中一个中断被忽略。 被忽略的 GPTtime 中断与被处理的中断相同。 我尝试使用单独的回调并在每个 GPTimer 的不同线程中进行脉冲捕获。

谢谢、
Kenneth

嘿、Kenneth、

您能否针对寄存器级或核心功能差异对我的代码设置进行评论？

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/*
 *  ======== timerled.c ========
 */

#include <stddef.h>
#include <unistd.h>

/* Driver Header files */
#include <ti/drivers/GPIO.h>
#include <ti/drivers/timer/GPTimerCC26XX.h>

/* Board Header file */
#include "ti_drivers_config.h"

#define MAX_GPTIMER_COUNT 16777215

GPTimerCC26XX_Handle GPTimer0;
GPTimerCC26XX_Handle GPTimer1;

uint8_t timerCount0 = 0;
uint8_t timerCount1 = 0;


void gptimerCallback(GPTimerCC26XX_Handle handle, GPTimerCC26XX_IntMask interruptMask) {
    // interrupt callback code goes here. Minimize processing in interrupt.
    if (handle == GPTimer0)
    {
        timerCount0++;
    }
    else if (handle == GPTimer1)
    {
        timerCount1++;
    }
}

/*
 *  ======== mainThread ========
 */
void *mainThread(void *arg0)
{

    /* Call driver init functions */
    GPIO_init();

    /* Configure the LED pin */
    GPIO_setConfig(CONFIG_GPIO_LED_0, GPIO_CFG_OUT_STD | GPIO_CFG_OUT_LOW);

    /* Turn off user LED */
    GPIO_write(CONFIG_GPIO_LED_0, CONFIG_GPIO_LED_OFF);

    GPTimerCC26XX_Params gptimer_params;
    GPTimerCC26XX_Params_init(&gptimer_params);
    gptimer_params.width          = GPT_CONFIG_16BIT;
    gptimer_params.mode           = GPT_MODE_EDGE_TIME;
    gptimer_params.matchTiming    = GPTimerCC26XX_SET_MATCH_NEXT_CLOCK;
    gptimer_params.direction      = GPTimerCC26XX_DIRECTION_UP;
    gptimer_params.debugStallMode = GPTimerCC26XX_DEBUG_STALL_OFF;

    // Open GPTimer and set argument to "this" object for callback to use
    GPTimer0 = GPTimerCC26XX_open(CONFIG_GPTIMER_0, &gptimer_params);
    GPTimer1 = GPTimerCC26XX_open(CONFIG_GPTIMER_1, &gptimer_params);

    GPTimerCC26XX_setArg(GPTimer0, (void *)0x00);
    GPTimerCC26XX_setArg(GPTimer1, (void *)0x01);

    GPTimerCC26XX_setLoadValue(GPTimer0, MAX_GPTIMER_COUNT);
    GPTimerCC26XX_setCaptureEdge(GPTimer0, GPTimerCC26XX_BOTH_EDGES);
    GPTimerCC26XX_registerInterrupt(GPTimer0, gptimerCallback, GPT_INT_CAPTURE);
    GPTimerCC26XX_start(GPTimer0);

    GPTimerCC26XX_setLoadValue(GPTimer1, MAX_GPTIMER_COUNT);
    GPTimerCC26XX_setCaptureEdge(GPTimer1, GPTimerCC26XX_BOTH_EDGES);
    GPTimerCC26XX_registerInterrupt(GPTimer1, gptimerCallback, GPT_INT_CAPTURE);
    GPTimerCC26XX_start(GPTimer1);

    GPIO_setConfigAndMux(CONFIG_GPIO_0, GPIO_CFG_IN_PU, GPTimerCC26XX_getPinMux(GPTimer0));
    GPIO_setConfigAndMux(CONFIG_GPIO_1, GPIO_CFG_IN_PU, GPTimerCC26XX_getPinMux(GPTimer1));

    while(1)
    {
        sleep(10);
    }

    return (NULL);
}

两个计时器都由同一中断提供服务、因为我可以看到 两个 timerCount 值的递增、但我只是使用一个开关(即没有电容器)下拉两个 GPIO 并短接至 GND、然后工作电压为3.3V、因此我不确定这些变量中是否有任何一个导致了可观察到的差异。

此致、
Ryan

嗨、Ryan、

您是否碰巧知道正在产生的脉冲的脉冲宽度？ 根据我们的观察结果、如果两个脉冲的脉冲宽度大约为10-12 微秒 、似乎会出现这个问题、但如果两个脉冲的脉冲宽度为490-500微秒、似乎可以正确处理这两个中断。

谢谢、
Kenneth

嗨、Ryan、

很抱歉晚才回复。 我离开了另一个项目。 我们决定最终 按顺序进行脉冲采集、然后将其移至传感器控制器以 降低功耗。

谢谢、
Kenneth T.