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https://e2e.ti.com/support/data-converters-group/data-converters/f/data-converters-forum/830630/ads54rf63-the-relation-of-each-of-the-differential-lines-vpp-and-total-differential-vpp
ADS54RF63数据表中的：说明这意味着每个输入的最大信号摆幅为1.1 VPP 、总差分输入信号摆幅为2.2 VPP。
但在我看来、它们 是等效的。
但是、我确保 TI 数据表不会出错、它必须具有特殊含义、您能告诉我这句话为什么正确吗？
Johnsen、
差分峰间电压将是正电压峰间值减去负电压峰间值或 Vdif = V+pp - V-pp 在本例中、数学运算结果为1.1Vpp (+)- 1.1Vpp (-)= 1.1 -(-1.1)= 2.2Vdiffpp。
优素福
