我正在尝试使用 ADC 从模拟加速计采集1k 个样本、并将其存储在数组中以供进一步处理、然后通过 MQTT 发送。 我是这方面的初学者、尝试了很多方法、包括使用计时器、但没有成功。 因此、我最终得到了以下代码、这些代码起作用、但我想知道这是否是一种好方法。
代码如下:我已使用 ACLK 时钟设置 ADC
static void setup_ADC(void){
ADC12CTL0 = ADC12SHT02 + ADC12ON; // Sampling time, ADC12 on
ADC12CTL1 = ADC12SHP + ADC12SSEL_1; // Use sampling timer; Pulse Sample Mode; ADC12SHT02 decides the interval of the sampling timer
// ACLK (32.768 kHz) selected as the clock source
ADC12IE = 0x01; // Enable interrupt
ADC12CTL0 |= ADC12ENC;
P6SEL |= 0x01; // P6.0 ADC option select
}
main 中的无限 while 循环具有 MQTT 函数、应在存储1000个样本后运行。
while(1){
/* Signal processing and communication only to be done after collecting 1K samples */
if (SamplesDone){
/* Send the values through mqtt */
mqtt();
samples_count = 0;
}
ADC12CTL0 |= ADC12SC; // Start sampling/conversion
__bis_SR_register(LPM0_bits + GIE); // LPM0, ADC12_ISR will force exit
__no_operation(); // For debugger
}
在 ISR 中、我只需将数据移动到可存储多达1000个元素的数组中
#if defined(__TI_COMPILER_VERSION__) || defined(__IAR_SYSTEMS_ICC__)
#pragma vector = ADC12_VECTOR
__interrupt void ADC12_ISR(void)
#elif defined(__GNUC__)
void __attribute__ ((interrupt(ADC12_VECTOR))) ADC12_ISR (void)
#else
#error Compiler not supported!
#endif
{
switch(__even_in_range(ADC12IV,34))
{
case 0: break; // Vector 0: No interrupt
case 2: break; // Vector 2: ADC overflow
case 4: break; // Vector 4: ADC timing overflow
case 6: // Vector 6: ADC12IFG0
adc_value = ADC12MEM0 & 0x0FFF; // keep only low 12 bits; Move results, IFG is cleared
adc_values[samples_count] = adc_value;
samples_count += 1;
/* Set the flag when 1000 samples are collected */
if (samples_count == 999) {
SamplesDone = 1;
}
__bic_SR_register_on_exit(LPM0_bits); // Exit active CPU
case 8: break; // Vector 8: ADC12IFG1
case 10: break; // Vector 10: ADC12IFG2
case 12: break; // Vector 12: ADC12IFG3
case 14: break; // Vector 14: ADC12IFG4
case 16: break; // Vector 16: ADC12IFG5
case 18: break; // Vector 18: ADC12IFG6
case 20: break; // Vector 20: ADC12IFG7
case 22: break; // Vector 22: ADC12IFG8
case 24: break; // Vector 24: ADC12IFG9
case 26: break; // Vector 26: ADC12IFG10
case 28: break; // Vector 28: ADC12IFG11
case 30: break; // Vector 30: ADC12IFG12
case 32: break; // Vector 32: ADC12IFG13
case 34: break; // Vector 34: ADC12IFG14
default: break;
}
}
我非常感谢对这种做法提出的任何建议/评论。