This assembly macro reads a result from the internal ADC module Result Register:n: and delivers it in Q24 format to the output terminal, where :n: is the instance number. The output is normalized to 0-1.0 such that the minimum input voltage will generate nominally 0.0 at the driver output, and a
maximum full scale input voltage read +1.0. The result is then stored in the memory location pointed to by the net terminal pointer.
上面的红色文字是说把输出结果归一化到0-1.0这个范围，但是下面汇编没有看到如何把输入电压结果归一化的。
ADCDRV_1ch_INIT .macro n
;================================
_ADCDRV_1ch_Rlt:n: .usect "ADCDRV_1ch_Section",2,1,1 ; output terminal 1
; publish Terminal Pointers for access from the C environment
.def _ADCDRV_1ch_Rlt:n:
MOVL XAR2, #ZeroNet ; "ZeroNet" is initialised to 0 in ISR
MOVW DP, #_ADCDRV_1ch_Rlt:n:
MOVL @_ADCDRV_1ch_Rlt:n:, XAR2 ; zero output terminal pointer
.endm
ADCDRV_1ch .macro n
;=============================
MOVW DP, #_ADCDRV_1ch_Rlt:n: ; Load Data Page
MOVL XAR0,@_ADCDRV_1ch_Rlt:n: ; Load Rlt Data Page Pointer in XAR0
MOVW DP, #_AdcResult ; load Data Page to read ADC results
MOV ACC,@_AdcResult.ADCRESULT:n:<<12 ; read and shift the 12 bit ADC result by 12 bits to get Q24 value
MOVL *XAR0,ACC ; store result in output pointer location
.endm
这个汇编程序如何把结果变成Q24格式的呢？这里结果左移12位不是变成Q12格式了吗？
谢谢
