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SCI Digital Loop Back with Interrupts.
发送的数据接收异常，可能是波特率不匹配的问题
#define CPU_FREQ 60E6#define LSPCLK_FREQ CPU_FREQ/4#define SCI_FREQ 100E3#define SCI_PRD (LSPCLK_FREQ/(SCI_FREQ*8))-1
这块没看明白，60E6代表多少，硬件没问题，跑例程 sci_echoback_cpu01波特率9600可以
JiaqI Liang 说：60E6代表多少
60*10^6HZ即 60MHz
