• 状态 Resolved
  • 已锁定 已锁定
  • 回复 6 回复
  • 订户 32 订户
  • 视图 2041 视图
  • 用户 0 会员在此处
选项
选项
相关

This thread has been locked.

If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.

关于TMS320F28069的问题

ruiping zhao
Intellectual 583 points


哪位大侠可以帮我一下吗？在user.h头文件中如下定义：

//! \brief Defines the location of the HRPWMENCLK bits in the PCLKCR0 register

//!

#define  CLK_PCLKCR0_HRPWMENCLK_BITS     (1 << 0)

 

//! \brief Defines the location of the LINAENCLK bits in the PCLKCR0 register

//!

#define  CLK_PCLKCR0_LINAENCLK_BITS      (1 << 1)

中 (1 << 0)，和  (1 << 1) 是什么意思？？

 

谢谢啦

  • 0
    TI__Guru 60308 points

    ruiping,

    1<<0, 表示1左移0位，

    1<<1 表示左移1位。

    这些是用在寄存器配置。

    Eric

  • 0
    TI__Expert 8058 points

    1 << 0：对bit0置1；

    #define  CLK_PCLKCR0_HRPWMENCLK_BITS     (1 << 0) 的意思是使能HRPWM模块的时钟信号；

    1 << 1：对bit1置1；（1左移1位）

    #define  CLK_PCLKCR0_LINAENCLK_BITS      (1 << 1)的意思是使能LIN模块的时钟信号；

     

  • 0 回复 Martin Yu
    Intellectual 583 points

    麻烦再追问一下，在头文件中有

    //! \brief Defines the number of bits per INTSELxNy register //! #define ADC_INTSELxNy_NUMBITS_PER_REG        8

    //! \brief Defines the log2() of the number of bits per INTSELxNy register //! #define ADC_INTSELxNy_LOG2_NUMBITS_PER_REG   3

    //! \brief Defines the location of the INTSEL bits in the INTSELxNy register //! #define ADC_INTSELxNy_INTSEL_BITS          (31 << 0)

    //! \brief Defines the location of the INTE bits in the INTSELxNy register //! #define ADC_INTSELxNy_INTE_BITS            (1 << 5)

    //! \brief Defines the location of the INTCONT bits in the INTSELxNy register //! #define ADC_INTSELxNy_INTCONT_BITS         (1 << 6)

    //! \brief Defines the location of the ACQPS bits in the ADCSOCxCTL register //! #define ADC_ADCSOCxCTL_ACQPS_BITS          (63 << 0)

    //! \brief Defines the location of the CHSEL bits in the ADCSOCxCTL register //! #define ADC_ADCSOCxCTL_CHSEL_BITS          (15 << 6)

    //! \brief Defines the location of the TRIGSEL bits in the ADCSOCxCTL register //! #define ADC_ADCSOCxCTL_TRIGSEL_BITS        (31 << 11)

    8在这里如何解释，  (15 << 6)如何解释，是15位左移6位吗， (31 << 11)，寄存器是最多32位吗，31位左移11位后变成什么了，不就又回到低位了？

    谢谢

  • 0 回复 ruiping zhao
    Guru 17055 points

    31=0x1F，左移11位为0xF800.对应着ADCSOCxCTL的TRIGSEL所在的高五位

  • 0 回复 Forrest
    Intellectual 680 points
    //! \brief Defines the location of the CHSEL bits in the ADCSOCxCTL register //! #define ADC_ADCSOCxCTL_CHSEL_BITS (15 << 6)
    请问这是对应哪个通道啊