F28335的ECAP问题

 我现在是采样50Hz的频率，配置如下：
void InitECap(void)
{
   // Initialize eCAP1
   ECap1Regs.ECEINT.all = 0x0000;             // Disable all capture interrupts
   ECap1Regs.ECCLR.all = 0xFFFF;              // Clear all CAP interrupt flags
   ECap1Regs.ECCTL2.bit.TSCTRSTOP = 0;        // Make sure the counter is stopped
   
   // Configure peripheral registers
   ECap1Regs.ECCTL2.bit.STOP_WRAP = 3;        // Stop at 4 events
   
   ECap1Regs.ECCTL1.bit.CAP1POL = 0;          // Rising edge
   ECap1Regs.ECCTL1.bit.CAP2POL = 1;          // Rising edge
   ECap1Regs.ECCTL1.bit.CAP3POL = 0;          // Rising edge
   ECap1Regs.ECCTL1.bit.CAP4POL = 1;          // Rising edge
   
   ECap1Regs.ECCTL1.bit.CTRRST1 = 0;          // ABS operation         
   ECap1Regs.ECCTL1.bit.CTRRST2 = 0;          // ABS operation         
   ECap1Regs.ECCTL1.bit.CTRRST3 = 0;          // ABS operation         
   ECap1Regs.ECCTL1.bit.CTRRST4 = 1;          // ABS operation     
       
   ECap1Regs.ECCTL2.bit.CONT_ONESHT = 0;      // Continuous
   ECap1Regs.ECCTL2.bit.SYNCI_EN = 0;         // Disable sync in
   ECap1Regs.ECCTL2.bit.SYNCO_SEL = 2;        // Pass through

   ECap1Regs.ECCTL2.bit.CAP_APWM = 0; //eCap Mode
   ECap1Regs.ECCTL2.bit.TSCTRSTOP = 1;        // Start Counter
   ECap1Regs.ECCTL1.bit.CAPLDEN = 1;          // Enable CAP1-CAP4 register loads
   ECap1Regs.ECEINT.bit.CEVT1 = 1;            // 1 events = interrupt
   ECap1Regs.ECEINT.bit.CEVT2 = 1;            // 2 events = interrupt
   ECap1Regs.ECEINT.bit.CEVT3 = 1;            // 3 events = interrupt
   ECap1Regs.ECEINT.bit.CEVT4 = 1;            // 4 events = interrupt
}

这是监视到中断里捕获的值，前面都正常，你看下[34]~[36]，为什么会有相同的几个值？