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如题，当选用INT10组的int1、int2时会进入interrupt void rsvd_ISR函数，而如果选用INT1组的int1、int2则不会出现这种现象，请问这是为什么呢？
lin zhou,
主要是没有对这里的向量入口初始化吧，默认是把interrupt void rsvd_ISR放在int和int2的入口的。
Eric
