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求助，将F28035例程Example_2803xAdcSoc里的INT1.1改为INT10.1后进不了ADC中断

Jian Zhang8
Prodigy 50 points


我需要降低ADC的优先级，参考F28035例程Example_2803xAdcSoc和文档TMS320F2803x Piccolo System Control and Interrupts

我现将例程原代码：PieCtrlRegs.PIEIER1.bit.INTx1 = 1;

                                   PieCtrlRegs.PIEACK.all = PIEACK_GROUP1;

                    改为：   PieCtrlRegs.PIEIER10.bit.INTx1 = 1;

                                   PieCtrlRegs.PIEACK.all = PIEACK_GROUP10;

但运行后不能进入ADC中断。谢谢！

  • 0
    Guru 56631 points

    每个中断都有自己的的PIEACK和INTx     这个要根据你的需要配置好

    你改了PIEACK GROUPx   不知道你改了对应中断的中断服务函数的入口地址了没？

  • 0
    Prodigy 50 points

    增加，原代码：IER |= M_INT1;

                    改为：IER |= M_INT10;

    此时运行进入rsvd_ISR中断。

  • 0 回复 Jian Zhang8
    Prodigy 50 points

    还得将DSP2803x_PieCtrl.h里的原代码：// Group 1 PIE Peripheral Vectors:
                                                                                   PINT   ADCINT1 ;                     // ADC - if Group 10 ADCINT1 is enabled, this must be rsvd1_1

                                                                             // Group 10 PIE Peripheral Vectors:
                                                                                  PINT     rsvd10_1;                    // Can be ADCINT1, but must make ADCINT1 in Group 1 space "reserved".

                                                                改为：  // Group 1 PIE Peripheral Vectors:
                                                                                   PINT     rsvd1_1;  

                                                                              // Group 10 PIE Peripheral Vectors:
                                                                                   PINT     ADCINT1;

    问题解决！

  • 0 回复 mangui zhang
    Prodigy 50 points

    谢谢，问题已经解决了。

  • 0 回复 Jian Zhang8
    Prodigy 50 points

    是DSP2803x_PieVect.h文件，刚才写错了。