请问CLA中 用 __sqrt 和 CLAsqrt有什么区别吗?
编译后,CLAsqrt占用的空间比 __sqrt 多12个字节。
interrupt void Cla1Task6 ( void )
{
A=CLAsqrt(B);
A=__sqrt(B);
}
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请问CLA中 用 __sqrt 和 CLAsqrt有什么区别吗?
编译后,CLAsqrt占用的空间比 __sqrt 多12个字节。
interrupt void Cla1Task6 ( void )
{
A=CLAsqrt(B);
A=__sqrt(B);
}