P6口上电后就有2.7V左右电压。将外部待采集电压接入后外部电压受到IO口输出电压的影响改变实际电压。特别是当采集小电压(零点几伏)时,电压被拉高到1.6V左右。请问这问题该如何解决??感谢解答!!
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P6口上电后就有2.7V左右电压。将外部待采集电压接入后外部电压受到IO口输出电压的影响改变实际电压。特别是当采集小电压(零点几伏)时,电压被拉高到1.6V左右。请问这问题该如何解决??感谢解答!!
这样配置是有问题的,建议参考官网的例程。
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//******************************************************************************
// MSP-FET430P140 Demo - ADC12, Sample A0, Set P1.0 if A0 > 0.5*AVcc
//
// Description: A single sample is made on A0 with reference to AVcc.
// Software sets ADC10SC to start sample and conversion - ADC12SC
// automatically cleared at EOC. ADC12 internal oscillator times sample (16x)
// and conversion. In Mainloop MSP430 waits in LPM0 to save power until ADC12
// conversion complete, ADC12_ISR will force exit from LPM0 in Mainloop on
// reti. If A0 > 0.5*AVcc, P1.0 set, else reset.
//
// MSP430F149
// -----------------
// /|\| XIN|-
// | | |
// --|RST XOUT|-
// | |
// Vin-->|P6.0/A0 P1.0|--> LED
//
// M. Buccini
// Texas Instruments Inc.
// Feb 2005
// Built with CCE Version: 3.2.0 and IAR Embedded Workbench Version: 3.21A
//******************************************************************************
#include <msp430.h>
int main(void)
{
WDTCTL = WDTPW + WDTHOLD; // Stop WDT
ADC12CTL0 = SHT0_2 + ADC12ON; // Set sampling time, turn on ADC12
ADC12CTL1 = SHP; // Use sampling timer
ADC12IE = 0x01; // Enable interrupt
ADC12CTL0 |= ENC; // Conversion enabled
P6SEL |= 0x01; // P6.0 ADC option select
P1DIR |= 0x01; // P1.0 output
for (;;)
{
ADC12CTL0 |= ADC12SC; // Sampling open
__bis_SR_register(CPUOFF + GIE); // LPM0, ADC12_ISR will force exit
}
}
// ADC12 interrupt service routine
#if defined(__TI_COMPILER_VERSION__) || defined(__IAR_SYSTEMS_ICC__)
#pragma vector=ADC12_VECTOR
__interrupt void ADC12_ISR (void)
#elif defined(__GNUC__)
void __attribute__ ((interrupt(ADC12_VECTOR))) ADC12_ISR (void)
#else
#error Compiler not supported!
#endif
{
if (ADC12MEM0 < 0x7FF)
P1OUT &= ~0x01; // Clear P1.0 LED off
else
P1OUT |= 0x01; // Set P1.0 LED on
__bic_SR_register_on_exit(CPUOFF); // Clear CPUOFF bit from 0(SR)
}