MSP430F5438 UART 如何接受超個8BIT

這是我的程式碼

#include "msp430x54x.h"

 #include "lcd.h"

  int a ;

void main(void)

 { 

WDTCTL = WDTPW + WDTHOLD;               

  P5SEL = BIT6+BIT7; 

   UCA1CTL1 |= UCSWRST;   

    UCA1CTL1 |= UCSSEL_1;                      

    UCA1BR0 = 3;                             

    UCA1BR1 = 0;                               

    UCA1MCTL |= UCBRS_3 + UCBRF_0;            

    UCA1CTL1 &= ~UCSWRST;                     

    UCA1IE |= UCRXIE;                                  

 __bis_SR_register(LPM3_bits + GIE);        

 __no_operation();                         }

#pragma vector=USCI_A1_VECTOR

 __interrupt void USCI_A1_ISR(void)

{

   switch(__even_in_range(UCA1IV,4))  

 {

   case 0:break;                         

     case 2:                                                            

   while (!(UCA1IFG&UCTXIFG));                     

       LCD_main();        

     if(a%2==0)          

      {              

    lcdlongint(3,0,UCA1RXBUF);                

  a++;      

    }      

else   

     {    

     lcdlongint(3,1,UCA1RXBUF);          

       a++;  

      }                           

        case 4:break;                   

            default: break;   

}

 }

因為我是利用RS-232連接讀卡機，因為讀卡機刷卡讀取卡號為40BIT(RS-232測試軟體讀到為191 191 191 191 223 )

但MSP430無法讀取從讀卡機傳來的卡號，但如果在8BIT以下的都讀取的到(RS-232測試軟體傳送8個BIT以下的MSP430 LCD都收的到)

請問有甚麼方式可以讓MSP430接收到40個BIT

我使用的軟體為CCS