如图，这个错误出现在进入ADC12中断的时候，我把ADC12这部分代码一并附上，这是什么原因啊？该怎么解决？
void ADC12_Initial(void){
P6SEL &= ~BIT6;
ADC12CTL0 &= ~ADC12ENC; // Set to 0
// Conversion memory start address, Timer Trigger, Repeat Single-Channel Conversion, Pulse-Mode, *ADC12 Clock source select SMCLK*
ADC12CTL1 = ADC12CSTARTADD_0 + ADC12SHS_1 + ADC12CONSEQ_2 + ADC12SHP /*+ ADC12SSEL_3*/;
// ADC On, 8 ADC12CLK Cycles, ADC Voltage Reference On, Voltage Reference 2.5V
ADC12CTL0 = ADC12ON + ADC12SHT0_1 + ADC12REFON + ADC12REF2_5V;
// ADC12 resolution 12 bits
ADC12CTL2 = ADC12RES_2;
// ADC Input select, V(R+) = VREF+ and V(R-) = AVSS
ADC12MCTL0 |= ADC12INCH_6 + ADC12SREF_1;
while (REFCTL0 & REFGENBUSY) // If Ref generator busy, wait
REFCTL0 |= REFVSEL_2 + REFON; // Select internal Ref = 2.5V, Internal Reference On
ADC12CTL0 |= ADC12ENC;
P6DIR &= ~BIT6; // Set P6.6 A6
TA0CTL = TASSEL_2 + MC_1; // Choose SMCLK, Up-Mode
TA0CCR1 = 49; // 5MHz/100KHz - 1 = 49
TA0CCTL1 = CAP + CCIE + CCIFG + OUTMOD_3; // Set/reset
TA0CTL |= TACLR + TAIE; // Enable interrupt, Clear TAR
__bis_SR_register(LPM0_bits + GIE); // Enter LPM0 w/ interrupts.在这里出错
}
#pragma vector=ADC12_VECTOR
__interrupt void ADC12ISR (void)
{
switch(__even_in_range(ADC12IV,34))
{
case 0: break; // Vector 0: No interrupt
case 2: break; // Vector 2: ADC overflow
case 4: break; // Vector 4: ADC timing overflow
case 6:
{
ADC12CTL0 |= ADC12SC;
ADC_Results[index] = ADC12MEM0;
}
break; // Vector 6: ADC12IFG0
case 8: break; // Vector 8: ADC12IFG1
case 10: break; // Vector 10: ADC12IFG2
case 12: break; // Vector 12: ADC12IFG3
case 14: break; // Vector 14: ADC12IFG4
case 16: break; // Vector 16: ADC12IFG5
case 18: break; // Vector 18: ADC12IFG6
case 20: break; // Vector 20: ADC12IFG7
case 22: break; // Vector 22: ADC12IFG8
case 24: break; // Vector 24: ADC12IFG9
case 26: break; // Vector 26: ADC12IFG10
case 28: break; // Vector 28: ADC12IFG11
case 30: break; // Vector 30: ADC12IFG12
case 32: break; // Vector 32: ADC12IFG13
case 34: break; // Vector 34: ADC12IFG14
default: break;
}
}
