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ADC采样时间的问题

hao ren
Prodigy 20 points
Other Parts Discussed in Thread: MSP430F5529

ADC配置为         

ADC12CTL0 = ADC12ON+ADC12SHT0_4+ADC12MSC;
 ADC12CTL1 = ADC12SHP+ADC12CONSEQ_3;

双通道10次采样取平均值，手册上脉冲采样时间如图，按(4 x ADC12CLK x N) + ( 13 xADC12CLK/Fadc12clk))计算得29ms，调试时总是MSP430F5529要快一些，希望得到帮助，谢谢

 

 

  • 0
    TI__Mastermind 18838 points

    你好，

    你可以把你在采样中断函数里面设置GPIO翻转的波形发出来吗？和29ms相比，看看翻转的速度是多少。

    最好是能把ADC采样这块程序也贴出来，我们才好在实验室里测试问题点。

  • 0 回复 kqian0327
    Prodigy 20 points

    图上传不了，翻转波形连续10次采样为26ms

    #pragma vector=ADC12_VECTOR
    __interrupt void ADC12ISR (void)
    {
    static unsigned int m,count = 0;
    float factor=0.80566;
    results1[count]=ADC12MEM0;
    results2[count]=ADC12MEM1;
    count++;
    for(m=0;m<10;m++)
    {
    sum1+=results1[m];
    sum2+=results2[m];
    }
    sum1/=10;
    com1=sum1*factor;

    sum2/=10;
    com2=sum2*factor/flag;

    sum3=com1*com2;
    com3=sum3;

    sum4+=sum3;
    com4=sum4*0.026; 

    sum5+=2.6;
    shijian=sum5;

    P7OUT ^= BIT0;

    if (count == 10)
    {
    count = 0;
    ADC12IE = 0x00;
    }
    }