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bq28z610 充电时,在FET_EN=0时,只需要开CHG即可吗?



我测试了下,1:只设置FET_EN=1后,即可充电;2:FET_EN=0; 只设置CHG=1,同样可充电;但是这两种情况下充满的条件判定不同;第1种方式当FC=1时则自动断开不进行充电了,第2种方式当FC=1时还在进行充电,直到 COV=1才断开不进行充电,,这样的种合理吗?为啥会有这样的区别呢?