如上图所示：软件代码是截取的官方demo，首先alarm_sta_A，alarm_sta_B，alarm_sta_C这几个寄存是8位单字节，程序使用16位双字节去读取，并且按位解析赋值个故障标志位，这是错误的，希望改正。
正题：
今天测试发现，AlarmStatus这个寄存器里有值是0x8000，但是，alarm_sta_B，alarm_sta_C里却没有任何值。alarm_sta_A的值，却在高8位上有个0x2000如图所示：
根据上面的描述：
问题1：为什么AlarmStatus报了0x8000,但是alarm_sta_B，alarm_sta_C却没有任何值
问题2：读alarm_sta_A时，读了两个字节出来，高8位到底什么？（PS:是 Safety Alert B Register 的值吗？）
您好，请参考下面的内容：
Thanks for pointing this out - there may be a bug in the example code for this function. If you read two bytes from this register, it will just read the following register as well. So in this case if 0x03 Safety Status A is being read, Safety Alert B is also being read (upper byte).
The variable names you mention (alarm_ sta_ A，alarm_ sta_ B，alarm_ sta_ C) are not in the code example though, so I am not sure how these are being read.
