Other Parts Discussed in Thread: EV2400
当产品进入过放保护后,通过MCU给Rst_shut引脚高电平使BQ76942进入shutdown,我们测试时发现放电MOS会重新开启再关闭,然后芯片才进入shutdown。请问这个是什么原因?
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您好,Do you have an scope image showing the LOW-HIGH-LOW voltage on DSG pin? I tried recreating this on the EVM and what I could see was a slightly increase in voltage of 0.5 V before entering shutdown mode, but this will not cause DSG FET to turn ON.
您好,The PDSG pin is floating on the schematic, but is enabled on the settings. I would disable the PDSG_EN bit in FET Options register.
Please try to enable SCD bit in DSG FET Protections A register. Please see below for what the TRM suggests. 
If these two suggestions do not help, I suggest trying this scenario with the default configurations to see if it is something from the configurations causing the DSG FET to turn ON. We have never seen the DSG FET turn on before shutdown.
您好,请参考下面的内容:
I recreated the testing procedure, and DSG FET will turn ON for approximately 750ms, then turn OFF. This happened when pulling up the RST_SHUTL pin. This happens regardless of CUV Delay time, so it is not depended to CUV Delay.
However, when sending the SHUTDOWN() subcommand, I did not see the DSG FET turning ON and OFF.
What it is happening here is that by pulling the RST_SHUTL pin high, the device does a partial reset before entering shutdown. The over-discharge protection flag will clear in partial reset causing the DSG FET to turn ON. Then, the device enters shutdown.
To avoid the partial reset, simply send SHUTDOWN() subcommand.
您好,工程师验证如下:
I tried on the bench the test with both CUV delays, and same result. I was able to recreate the DSG FET behavior with CUV = 74ms and 604ms. The CUV delay did not make a difference. This might be something to fix for future devices.
I suggest to use the SHUTDOWN() subcommand.