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LM5157: The relationship between BIAS Pin and the internal VCC regulator, the uses of the diode connected between BIAS and VCC regulator output

Part Number: LM5157


 (1) In the datasheet, there is a description: it can operate with an input supply voltage as low as 1.5V if the BIAS pin is greater than 2.9V.  I don't know the reason and the logic of this sentence. How does the BIAS Pin voltage influence the minimum supply voltage? As I known, the BIAS Pin usually connects to V(supply) directly in fly-back. in this condition, the V(BIAS) is equal to V(supply).

(2) There is a diode connected between BIAS and VCC regulator’s output, what is the uses of this diode?

This is my assumption: When the V(BIAS) less than 5V, the diode is forward and the output voltage of the VCC regulator is equal to V(BIAS). I guess this can explain the curves shown in datasheet (see Fig7-4 in datasheet) However, there is another question: why the VCC regular voltage change with V(BIAS) but not be a constant value (5 V) when the VBIAS below 5V? Will the low voltage (below 5V) influence its driven capability for internal MOSFET?

  • HI

        1. 芯片将输入电压和偏执电压分开,就是为了更低的输入电压,因为偏执电压是给芯片内部供电,这个电压不能太低, 所以不能将偏执电压取电Vin。也就是说要1.5V输入,偏执电压需要另外供电。

        2. 你可以理解偏执电压是LDO的输入,Vcc是LDO的输出,正常偏执电压都是高于Vcc, 二极管是不工作的,这个二极管主要起保护作用。