核0主程序:
void main()
{
IER= 0;
//eanble TSC Initialize Time stamp counter to measure cycles
TSC_init();
for(;;)
{
IssueInterruptToNextCore();//往核1发IPC中断
TSC_delay_ms(3);
}
}
核0 的IPC发
void IssueInterruptToNextCore()
{
uint32_t interruptInfo=0;
interruptInfo +=16;
// Unlock Config
//KICK0 = KICK0_UNLOCK;
//KICK1 = KICK1_UNLOCK;
*(volatile uint32_t *) iIPCGRInfo[1] = interruptInfo;
*(volatile uint32_t *) iIPCGRInfo[1] |= 1;
// lock Config
//KICK0 = KICK_LOCK;
//KICK1 = KICK_LOCK;
interruptNumber0++;
}
核1主程序：
void main()
{
IER= 0;
//eanble TSC Initialize Time stamp counter to measure cycles
TSC_init();
GPIO_init(); //GPIO初始化
IPC_Interrupts_Init(); //IPC中断初始化
//clear DSP core interrupt flag
ICR= IFR;
/*Interrupt Service Table Pointer to begining of LL2 memory*/
ISTP= 0x11800000;
//enable NMIE&中断
IER = 3|(1<<4);
//enable GIE Enables all interrupts.
TSR = TSR|1;
while(1)
{
//DOG0();
}
}
核1 的IPC中断
void IPC_ISR()
{
volatile uint32_t read_ipcgr;
read_ipcgr = *(volatile Uint32 *) iIPCGRInfo[1];
*(volatile uint32_t *) iIPCARInfo[1] = read_ipcgr; //clear the related source info
interruptNumber1++;
}
核1 的IPC中断初始化
void IPC_Interrupts_Init(void)
{
//Contains the number of the event that maps to DSPINTnn
gpCGEM_regs->INTMUX1 = 0;
gpCGEM_regs->INTMUX2 = 0;
gpCGEM_regs->INTMUX3 = 0;
//map local timer interrupt to INT13
gpCGEM_regs->INTMUX1 |= (CSL_GEM_IPC_LOCAL<<CSL_CGEM_INTMUX1_INTSEL4_SHIFT);
}
现在的问题是 如果把核1主程序while(1)中的DOG0()屏蔽掉 那么双核间的中断就是正常的 核0发多少次 核1就响应多少次！
如果把核1主程序while(1)中的DOG0())不屏蔽 那么双核间的中断就不正常 核0发很多次 核1只响应一次！
试了多次 总结出的规律就是：
核1主程序while(1)中不能执行其他语句，只能空跑！！！
哪位大神给解释下 完整例程在附件！！！1122.IPC0.rar1832.IPC1.rar
