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请问一下，我现在用EMIFA连接16位的RAM，假设我的地址是0x60000000,然后到RAM里面的地址是和BA1拼接的地址，与之对应的地址是0x60002000吗
例如对于两次16bit ram访问在DSP内部来看是一样的32位地址，只是通过BA[1]来区分。
可阅读以下与FPGA通信的讨论：
https://e2e.ti.com/support/processors-group/processors/f/processors-forum/365309/address-mapping-to-6748-emif-and-ba-1-behavior
DSP(0x62000000) with (BA[1]=0) = FPGA(0x000)
DSP(0x62000000) with (BA[1]=1) = FPGA(0x001)
DSP(0x62000001) with (BA[1]=0) = FPGA(0x002)
DSP(0x62000001) with (BA[1]=1) = FPGA(0x003)
手册中给出的地址范围并不是真正的内存空间，只是映射，如果访问0x60000000就是访问0地址，0x60000001就是访问1地址。
