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tivxSetNodeParameterNumBufByIndex(obj->tidlObj.node, 4, 2); 在09.01.00.06版本 跑不起来为输入节点，在08.00.04版本跑的没问题
其中的“4”是怎么来的
index -- 4 or index--7 这些数字的含义哪里定义
请参考下面的帖子。
The value 4 and 7 represents the node parameter index for the TIDL node.
If you see the node api of TIDL node,
tivxTIDLNode(vx_graph graph, vx_kernel kernel, vx_reference appParams[], vx_tensor input_tensors[], vx_tensor output_tensors[])
appParams[] consists of 6 parameters (i.e. 0 to 5) , namely config, network, createparams, in_args, out_args and tracedata
input_tensor index is 6 and output tensor index is 7 (assuming there is 1 input tensor and 1 output tensor)
So here 4 is out_args and 7 is output tensor
https://e2e.ti.com/support/processors-group/processors/f/processors-forum/894343/tda4vmxevm-how-to-set-tivxsetnodeparameternumbufbyindex
在 09.00.01.06这个版本的软件中，去掉了 4 这一步。我也跟着去掉了，没有了先前的错误，但是出现了新的错误：vxWaitGraph:871 graph not in expected state； 这个是openvx接口
新问题麻烦另起新帖，方便其他客户参考，谢谢！
