你好：
最近在看6678芯片DDR3方面的东西，在官方论坛www.deyisupport.com/.../2622.aspx中 Andy Yin1提供的
Keystone1_Memory.7z的三个工程中，关于Memory_Sharing这个工程有些疑问：
1.工程MEM_share_EDMA_Timer_Intc_setup.c源文件中函数：
void CP_INTC_Init_EDMA(void)
{
TDSP_Board_Type DSP_Board_Type;
/* Disable Global host interrupts. */
cpIntc0Regs->GLOBAL_ENABLE_HINT_REG= 0;
DSP_Board_Type= KeyStone_Get_dsp_board_type();
if(C6670_EVM==DSP_Board_Type
||DUAL_NYQUIST_EVM==DSP_Board_Type
||TCI6614_EVM==DSP_Board_Type)
{
uiEdma_host_event_num[0]= 74;
uiEdma_host_event_num[1]= 84;
uiEdma_host_event_num[2]= 94;
/*map EDMA0, 1, 2 GINT interrupts events (36, 6, 22) to INTC0 out74, 84, 94*/
cpIntc0Regs->CH_MAP[SWAP_ENDIAN(36)]= 74;
cpIntc0Regs->CH_MAP[SWAP_ENDIAN(6)]= 84;
cpIntc0Regs->CH_MAP[SWAP_ENDIAN(22)]= 94;
/*enable INTC out74, 84, 94*/
cpIntc0Regs->HINT_ENABLE_SET_INDEX_REG= 74;
cpIntc0Regs->HINT_ENABLE_SET_INDEX_REG= 84;
cpIntc0Regs->HINT_ENABLE_SET_INDEX_REG= 94;
}
else if(C6678_EVM==DSP_Board_Type)
{
uiEdma_host_event_num[0]= 44;
uiEdma_host_event_num[1]= 55;
uiEdma_host_event_num[2]= 66;
第一步：
/*map EDMA0, 1, 2 GINT interrupts events (36, 6, 22) to INTC0 out44, 55, 66*/
cpIntc0Regs->CH_MAP[SWAP_ENDIAN(36)]= 44;
cpIntc0Regs->CH_MAP[SWAP_ENDIAN(6)]= 55;
cpIntc0Regs->CH_MAP[SWAP_ENDIAN(22)]= 66;
第二步：
/*enable INTC out44, 55, 66*/
cpIntc0Regs->HINT_ENABLE_SET_INDEX_REG= 44;
cpIntc0Regs->HINT_ENABLE_SET_INDEX_REG= 55;
cpIntc0Regs->HINT_ENABLE_SET_INDEX_REG= 66;
}
else
{
puts("Unknown DSP board type!");
return;
}
第三步：
/*clear EDMA0, 1, 2 GINT interrupts events (36, 6, 22)*/
cpIntc0Regs->STATUS_CLR_INDEX_REG= 6;
cpIntc0Regs->STATUS_CLR_INDEX_REG= 22;
cpIntc0Regs->STATUS_CLR_INDEX_REG= 36;
第四步：
/*enable EDMA0, 1, 2 GINT interrupts events (36, 6, 22)*/
cpIntc0Regs->ENABLE_SET_INDEX_REG= 6;
cpIntc0Regs->ENABLE_SET_INDEX_REG= 22;
cpIntc0Regs->ENABLE_SET_INDEX_REG= 36;
第五步：
/* Enable Global host interrupts. */
cpIntc0Regs->GLOBAL_ENABLE_HINT_REG= 1;
}
程序中标红部分，数组中依次写值44/55/66，这三个数的来源是什么，与EDMA0, 1, 2 GINT interrupts events (36, 6, 22)的什么关系？是随意写的吗？还是有什么规则？有规则的话出处在哪？
2.工程MEM_share_EDMA_Timer_Intc_setup.c源文件中函数：
void EDMA_Timer_Interrupts_Init(void)
{
/*on Nyquist, INTC0 out74, out84, out94 event number are 22 on core 1, 2, 3
on Shannon, INTC0 out44, out55, out66 event number are 22 on core 1, 2, 3
map this event 22 to INT8 */
CGEM_regs->INTMUX2 = 22<<CSL_CGEM_INTMUX2_INTSEL8_SHIFT;
//map timer interrupt to INT14
CGEM_regs->INTMUX3 = CSL_GEM_TINTLN<<CSL_CGEM_INTMUX3_INTSEL14_SHIFT;
/*Clear all DSP core events*/
CGEM_regs->EVTCLR[0]= 0xFFFFFFFF;
CGEM_regs->EVTCLR[1]= 0xFFFFFFFF;
CGEM_regs->EVTCLR[2]= 0xFFFFFFFF;
CGEM_regs->EVTCLR[3]= 0xFFFFFFFF;
//clear DSP core interrupt flag
ICR= IFR;
//enable INT8, 14
IER = 3|(1<<8)|(1<<14);
/*Interrupt Service Table Pointer to begining of LL2 memory*/
ISTP= 0x800000;
//enable GIE
TSR = TSR|1;
}
函数中标红部分将事件22映射到INT8，查看对应PDF文档TMS320C6678 Multicore Fixed and Floating-Point Digital Signal Processor Data Manual中7.9.1的Table7-38，截图如下：
对应其中22，我想知道CIC0_OUT(32+1+11*n) (7) Or CIC1_OUT(32+1+11*(n-4)) (7) 中n是什么意思？INTC0 out44, out55, out66这三个out与事件22是怎么样一种关系呢？是如何连接或者映射到一起的呢？映射机制出处在哪？
疑问较多，麻烦TI工程师了，请不吝解疑。
非常感谢！
