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AWR2243: 关于AWR2243如何校准移相器的问题(How to calibrate phase shifter in AWR2243)

Part Number: AWR2243

中文 : Ti的datasheet里面关于移相器写的是6位,这里是AWR2243读出目前校准的相位值,文档里圈起来的地方1 LSB是除以2^10,(理解起来应该是用精度更高位的10位来做校准),但是文档里圈起来的地方(观测的相位值被存储在两个8位字节中,那按理1 LSB应该是除以2^16,所以不是很理解是怎么校准的,对应关系是怎样的? 请帮忙解答一下,不甚感激!

English: The Ti datasheet for phase shifter is 6 bits, here is AWR2243 read the current calibrated phase value, circled in the document 1 LSB is divided by 2^10, (understanding should be using the higher precision 10 bits to do the calibration), But circled in the document (the observed phase value is stored in two 8-bit bytes, so logically 1 LSB should be divided by 2^16, so it's not quite clear how it's calibrated, what's the correspondence? Please help to answer, I am very grateful!

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