uart_echo_xwrL64xx-evm_m4fss0-0_nortos_ti-arm-clang的uart-J9.13
1：在< example.syscfg>把UART_TX pin 从PAD_A0/E10设置为PAD_AN/L12，
把USB转TTL的RXD管脚连接到J9.09(XDS_UARTA_TX)，
重新编译，在SSCOM上可以看到收发正常。
2：在< PROC117B(001_IWR)_Sch.PDF>的R147焊接上0欧电阻后，
在< example.syscfg>把UART_RX pin 从PAD_AP/F11设置为PAD_AM/J11，
把USB转TTL的TXD管脚连接到J9.13(XDS_UARTA_RX)上。
重新编译，在SSCOM上可以看到收发不正常，
文件uart_echo.c的函数uart_echo的UART_read接收不到数据。
/*
* Copyright (C) 2021 Texas Instruments Incorporated
*
* Redistribution and use in source and binary forms, with or without
* modification, are permitted provided that the following conditions
* are met:
*
* Redistributions of source code must retain the above copyright
* notice, this list of conditions and the following disclaimer.
*
* Redistributions in binary form must reproduce the above copyright
* notice, this list of conditions and the following disclaimer in the
* documentation and/or other materials provided with the
* distribution.
*
* Neither the name of Texas Instruments Incorporated nor the names of
* its contributors may be used to endorse or promote products derived
* from this software without specific prior written permission.
*
* THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS
* "AS IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT
* LIMITED TO, THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR
* A PARTICULAR PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT
* OWNER OR CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL,
* SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT
* LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE,
* DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY
* THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT
* (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE
* OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
*/
/* This example demonstrates the UART RX and TX operation by echoing char
* that it recieves in blocking, interrupt mode of operation.
* When user types 'quit', the application ends.
*/
#include <string.h>
#include <kernel/dpl/DebugP.h>
#include "ti_drivers_config.h"
#include "ti_drivers_open_close.h"
#include "ti_board_open_close.h"
#define APP_UART_BUFSIZE (200U)
#define APP_UART_RECEIVE_BUFSIZE (8U)
uint8_t gUartBuffer[APP_UART_BUFSIZE];
uint8_t gUartReceiveBuffer[APP_UART_RECEIVE_BUFSIZE];
volatile uint32_t gNumBytesRead = 0U, gNumBytesWritten = 0U;
#define APP_UART_ASSERT_ON_FAILURE(transferOK, transaction) \
do { \
if((SystemP_SUCCESS != (transferOK)) || (UART_TRANSFER_STATUS_SUCCESS != transaction.status)) \
{ \
DebugP_assert(FALSE); /* UART TX/RX failed!! */ \
} \
} while(0) \
void uart_echo(void *args)
{
int32_t transferOK;
UART_Transaction trans;
Drivers_open();
Board_driversOpen();
DebugP_log("[UART] Echo example started ...\r\n");
UART_Transaction_init(&trans);
/* Send entry string */
gNumBytesWritten = 0U;
trans.buf = &gUartBuffer[0U];
strncpy(trans.buf,"This is uart echo test blocking mode\r\nReceives 8 characters then echo's back. Please input..\r\n", APP_UART_BUFSIZE);
trans.count = strlen(trans.buf);
transferOK = UART_write(gUartHandle[CONFIG_UART_CONSOLE], &trans);
APP_UART_ASSERT_ON_FAILURE(transferOK, trans);
/* Read 8 chars */
gNumBytesRead = 0U;
trans.buf = &gUartReceiveBuffer[0U];
trans.count = APP_UART_RECEIVE_BUFSIZE;
transferOK = UART_read(gUartHandle[CONFIG_UART_CONSOLE], &trans);
APP_UART_ASSERT_ON_FAILURE(transferOK, trans);
/* Echo chars entered */
gNumBytesWritten = 0U;
trans.buf = &gUartReceiveBuffer[0U];
trans.count = APP_UART_RECEIVE_BUFSIZE;
transferOK = UART_write(gUartHandle[CONFIG_UART_CONSOLE], &trans);
APP_UART_ASSERT_ON_FAILURE(transferOK, trans);
/* Send exit string */
gNumBytesWritten = 0U;
trans.buf = &gUartBuffer[0U];
strncpy(trans.buf, "\r\nAll tests have passed!!\r\n", APP_UART_BUFSIZE);
trans.count = strlen(trans.buf);
transferOK = UART_write(gUartHandle[CONFIG_UART_CONSOLE], &trans);
APP_UART_ASSERT_ON_FAILURE(transferOK, trans);
DebugP_log("All tests have passed!!\r\n");
Board_driversClose();
Drivers_close();
return;
}
1）您是否可以通过另一个 USB 到 UART 桥接器进行确认？ 或者在其测试中使用，以确保 USB 电桥的 TX 不出现故障？
用2个USB 到 UART 桥接器电脑sscom显示通信成功。
用2个USB 到 UART 桥接器电脑sscom显示通信成功_收发数据图.png
用2个USB 到 UART 桥接器电脑sscom显示通信成功_连接图.jpg
换了一个 USB 到 UART 桥接器，作为实验
2）在测试时 EVM 是如何供电的？ 从图中看好像有导线焊接到桶形插孔连接器引脚上。 能否改为使用 Micro USB 端口提供的功率来测试此情况？
在测试时 EVM 是如何供电的：使用 Micro USB 端口供电。
图中看好像有导线焊接到桶形插孔连接器引脚上：没有连接，悬空。
uart_echo_uart桥接器_microusb端口供电.jpg
3）贵公司该实验做过吧？这个问题已经挺长时间了。我们在工程里面需要双uart，能否提供：
3.1）实现双uart的iwrl6432板；
3.2）配套的双uart源代码。
谢谢！
一：针对贵公司的回复内容：
您好，
从图片来看没有什么问题。
您可以参考以下关于进一步调试的建议：
1）您是否可以通过另一个 USB 到 UART 桥接器进行确认？ 或者在其测试中使用，以确保 USB 电桥的 TX 不出现故障？
2）在测试时 EVM 是如何供电的？ 从图中看好像有导线焊接到桶形插孔连接器引脚上。 能否改为使用 Micro USB 端口提供的功率来测试此情况？
二：回复如下：
1）您是否可以通过另一个 USB 到 UART 桥接器进行确认？ 或者在其测试中使用，以确保 USB 电桥的 TX 不出现故障？
用2个USB 到 UART 桥接器电脑sscom显示通信成功。
用2个USB 到 UART 桥接器电脑sscom显示通信成功_收发数据图.png
用2个USB 到 UART 桥接器电脑sscom显示通信成功_连接图.jpg
换了一个 USB 到 UART 桥接器，作为实验
2）在测试时 EVM 是如何供电的？ 从图中看好像有导线焊接到桶形插孔连接器引脚上。 能否改为使用 Micro USB 端口提供的功率来测试此情况？
在测试时 EVM 是如何供电的：使用 Micro USB 端口供电。
图中看好像有导线焊接到桶形插孔连接器引脚上：没有连接，悬空。
uart_echo_uart桥接器_microusb端口供电.jpg
三：贵公司该实验做过吧？这个问题已经挺长时间了。我们在工程里面需要双uart，能否提供：
实现双uart的iwrl6432板；
配套的双uart源代码。
