CC2530 IO口初始化

下面的是我试过的方式一：
#define LED_Switch1 P0_3            //mode A
#define LED_Switch2 P0_4            //mode B
#define LED_Switch3 P0_5            //mode C
#define LED_Switch4 P0_2            //mode C

#define Solution0   LED_Switch1=1;LED_Switch2=0;LED_Switch3=0;  //A    P0.3
#define Solution1   LED_Switch1=1;LED_Switch2=1;LED_Switch3=0;  //B    P0.3+P0.4
#define Solution2   LED_Switch1=0;LED_Switch2=1;LED_Switch3=0;  //C    P0.4
#define Solution3   LED_Switch1=0;LED_Switch2=1;LED_Switch3=1;  //A+B  P0.4+P0.5
#define Solution4   LED_Switch1=0;LED_Switch2=0;LED_Switch3=1;  //B+C  P0.5
#define SolutionC   LED_Switch1=0;LED_Switch2=0;LED_Switch3=0;  //close all

下面的是方式二：
#define Solution0   P0 = 0x34; //A    P0.3
#define Solution1   P0 = 0x24; //B    P0.3+P0.4
#define Solution2   P0 = 0x2C; //C    P0.4
#define Solution3   P0 = 0x08; //A+B  P0.4+P0.5
#define Solution4   P0 = 0x18; //B+C  P0.5
#define SolutionC   P0 = 0xFF; //close all  

下面是对IO的初始化：
    PERCFG |= 0x43;		//timer1 io 备用2   
    P0SEL  = 0xC0;		//1:外设，0:普通IO；timer1 通道4 P0_6 0xcc for uart  0xc0 no uart  

    P0DIR |= 0x7C;              //0:输入，1:输出;
    
    P0INP &= 0x83;              //P0.5上拉 0上下拉，由2定。1000 0011 2,3,4,5,6上拉
    P2INP &= 0xDF;              //P0上拉 0上拉 1101 1111
    
    //P1口的0用于测试PWM用
    P1SEL |= 0x01;		//1:外设，0:普通IO；timer2 通道2 LED1 P1_0
    P1DIR |= 0x01;              //0:输入，1:输出;
    
    P0 |= 0x7C;                 // |0x7C初始化P0.2 0.3 .4 .5 .6为高 0111 1100
    
    //ADC设置
    APCFG = 0x80;              //P0.7用作模拟口

下面是函数调用：
    switch(Data_Buf[3])
    {
      case 0:
      {
      Solution0;  
      }break;
      case 1:
      {
      Solution1;      
      }break;
      case 2:
      {
      Solution2;      
      }break;
      case 3:
      {
      Solution3;       
      }break;
      case 4:
      {
      Solution4;    
      }break;
                      
      default : 
      break;                           
    }

现象是0.4始终为低，但是我如果去掉宏定义时的LED_Switch4（P0.2），那么就是0.5口始终为低。