[参考译文] Eratta -AM243X：我们如何识别 MCU-PLUS-SDK i2310中描述的潜在故障

您好：Mark、

指定的 IS 专家今天已离职。 对此主题的响应将延迟。 感谢您的合作。

此致、

Tushar

尊敬的 Tushar：

是否有任何更新？

谢谢、Merril

您好、

感谢您的耐心。

我已跟踪 i2310的提交所有者、现在可以在 MCU PLUS SDK 的 drivers/UART 下看到。

我将讨论并在我有更新后通知您。

此致、

Vaibhav

您好、

我需要更多的时间来评论我对此的想法。

此致、

Vaibhav

尊敬的 Vaibhav：

是否有任何更新？

谢谢、Merril

您好 Newman：

我尝试在 AM243 LP TI EVM 上重现此问题。

这里的目标如下。

请检查我的测试应用程序。 请注意、我已在 API UART_i2310WA 处放置一个断点、看看它是否达到它、因此我可以从中得出一些结论。

/*
 *  Copyright (C) 2021 Texas Instruments Incorporated
 *
 *  Redistribution and use in source and binary forms, with or without
 *  modification, are permitted provided that the following conditions
 *  are met:
 *
 *    Redistributions of source code must retain the above copyright
 *    notice, this list of conditions and the following disclaimer.
 *
 *    Redistributions in binary form must reproduce the above copyright
 *    notice, this list of conditions and the following disclaimer in the
 *    documentation and/or other materials provided with the
 *    distribution.
 *
 *    Neither the name of Texas Instruments Incorporated nor the names of
 *    its contributors may be used to endorse or promote products derived
 *    from this software without specific prior written permission.
 *
 *  THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS
 *  "AS IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT
 *  LIMITED TO, THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR
 *  A PARTICULAR PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT
 *  OWNER OR CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL,
 *  SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT
 *  LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE,
 *  DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY
 *  THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT
 *  (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE
 *  OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
 */

/* This example demonstrates the UART RX and TX operation by echoing char
 * that it recieves in blocking, interrupt mode of operation.
 * When user types 'quit', the application ends.
 */

#include <string.h>
#include <kernel/dpl/DebugP.h>
#include "ti_drivers_config.h"
#include "ti_drivers_open_close.h"
#include "ti_board_open_close.h"

#define APP_UART_BUFSIZE              (200U)
#define APP_UART_RECEIVE_BUFSIZE      (8U)

uint8_t gUartBuffer[APP_UART_BUFSIZE];
uint8_t gUartReceiveBuffer[APP_UART_RECEIVE_BUFSIZE];
volatile uint32_t gNumBytesRead = 0U, gNumBytesWritten = 0U;

#define APP_UART_ASSERT_ON_FAILURE(transferOK, transaction) \
    do { \
        if((SystemP_SUCCESS != (transferOK)) || (UART_TRANSFER_STATUS_SUCCESS != transaction.status)) \
        { \
            DebugP_assert(FALSE); /* UART TX/RX failed!! */ \
        } \
    } while(0) \

void uart_echo(void *args)
{
    int32_t          transferOK;
    UART_Transaction trans;

    Drivers_open();
    Board_driversOpen();

    DebugP_log("[UART] Echo example started ...\r\n");

    uint32_t tries = 1000;
    while(tries > 0)
    {
        tries--;
        UART_Transaction_init(&trans);

        /* Send entry string */
        gNumBytesWritten = 0U;
        trans.buf   = &gUartBuffer[0U];
        strncpy(trans.buf,"This is uart echo test blocking mode\r\nReceives 8 characters then echo's back. Please input..\r\n", APP_UART_BUFSIZE);
        trans.count = strlen(trans.buf);
        transferOK = UART_write(gUartHandle[CONFIG_UART_CONSOLE], &trans);
        APP_UART_ASSERT_ON_FAILURE(transferOK, trans);

        /* Read 8 chars */
        gNumBytesRead = 0U;
        trans.buf   = &gUartReceiveBuffer[0U];
        trans.count = APP_UART_RECEIVE_BUFSIZE;

        for(int i = 0; i < 8; i++) gUartReceiveBuffer[i] = 97 + i;

//        transferOK = UART_read(gUartHandle[CONFIG_UART_CONSOLE], &trans);
//        APP_UART_ASSERT_ON_FAILURE(transferOK, trans);

        /* Echo chars entered */
        gNumBytesWritten = 0U;
        trans.buf   = &gUartReceiveBuffer[0U];
        trans.count = APP_UART_RECEIVE_BUFSIZE;
        transferOK = UART_write(gUartHandle[CONFIG_UART_CONSOLE], &trans);
        APP_UART_ASSERT_ON_FAILURE(transferOK, trans);

        /* Send exit string */
        gNumBytesWritten = 0U;
        trans.buf   = &gUartBuffer[0U];
        strncpy(trans.buf, "\r\nAll tests have passed!!\r\n", APP_UART_BUFSIZE);
        trans.count = strlen(trans.buf);
        transferOK = UART_write(gUartHandle[CONFIG_UART_CONSOLE], &trans);
        APP_UART_ASSERT_ON_FAILURE(transferOK, trans);

        DebugP_log("All tests have passed!!\r\n");
    }

    Board_driversClose();
    Drivers_close();

    return;
}

此致、

Vaibhav

我已经浏览了代码、并列出了一些我已经缩小的内容。

有一个名为 UART_IIR_UART 的寄存器

这将告诉我们中断类型、或者更正式地说明当前生成的中断类型。

只关注黄色突出显示部分。  

如果从 UART_IIR 寄存器读取的值为 1100 B、这意味着中断是 RX 超时读取6h。

如果发生这种情况、我们会检查是否需要读取至少1个字节：

1. 如果没有要读取的字节、我们最好继续。
2. 如果是、我们会看到勘误表 i2310
   

你好、Vaibhav、  

我们没有简单的方法来读取  UART_EFR2寄存器、因为我们的生产固件 对此寄存器没有直接打印。  

鉴于这是 TI 端已知的勘误表、根据上面的脚本日志、您能否帮助确认这些勘误表是否都源于此 UART 引导勘误表？   


谢谢、  
Hong