[参考译文] TMS320F28034：ADC：初始转换、第一个采样也许不是正确的转换结果、或者被丢弃？

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https://e2e.ti.com/support/microcontrollers/c2000-microcontrollers-group/c2000/f/c2000-microcontrollers-forum/1273934/tms320f28034-adc-initial-conversion-the-first-sample-may-not-be-the-correct-conversion-result-or-discard

器件型号：TMS320F28034

您好、专家！

我要求在这里为我的客户提供帮助。

他们使用80引脚 F28034-PN 来开发 HVAC、还发现了有关 ADC 初始转换的以下限制。

下面是客户 ADC 代码、他们使用 EPWM1_SOCA 触发顺序 SOC0~SOC11和 SOC15、同时他们还使用 EPWM4_SOCB 触发顺序 SOC12、SOC13 和 SOC14。因此、根据勘误手册、ADCRESULT0和 ADCRESULT12会缺失或不正确、对吗？如果是、错误会消失多远？

EALLOW;
AdcRegs.ADCCTL1.bit.RESET = 1;

asm(" NOP ");
asm(" NOP ");

AdcRegs.ADCCTL1.bit.ADCREFSEL = 0;
AdcRegs.ADCCTL1.bit.ADCBGPWD = 1;
AdcRegs.ADCCTL1.bit.ADCREFPWD = 1;
AdcRegs.ADCCTL1.bit.ADCPWDN = 1;
AdcRegs.ADCCTL1.bit.ADCENABLE = 1;
(*Device_cal)();
asm(" RPT#100 || NOP");

DELAY_US(ADC_usDELAY);

AdcRegs.ADCCTL1.bit.INTPULSEPOS = 0;
AdcRegs.ADCCTL2.bit.ADCNONOVERLAP = 1;

AdcRegs.ADCSOC0CTL.bit.ACQPS = 6;
AdcRegs.ADCSOC1CTL.bit.ACQPS = 25;
AdcRegs.ADCSOC2CTL.bit.ACQPS = 25;
AdcRegs.ADCSOC3CTL.bit.ACQPS = 6;
AdcRegs.ADCSOC4CTL.bit.ACQPS = 6;
AdcRegs.ADCSOC5CTL.bit.ACQPS = 6;
AdcRegs.ADCSOC6CTL.bit.ACQPS = 6;
AdcRegs.ADCSOC7CTL.bit.ACQPS = 6;
AdcRegs.ADCSOC8CTL.bit.ACQPS = 6;
AdcRegs.ADCSOC9CTL.bit.ACQPS = 6;
AdcRegs.ADCSOC10CTL.bit.ACQPS = 6;
AdcRegs.ADCSOC11CTL.bit.ACQPS = 6;
AdcRegs.ADCSOC12CTL.bit.ACQPS = 6;
AdcRegs.ADCSOC13CTL.bit.ACQPS = 6;
AdcRegs.ADCSOC14CTL.bit.ACQPS = 30;
AdcRegs.ADCSOC15CTL.bit.ACQPS = 6;

AdcRegs.ADCSOC0CTL.bit.CHSEL= 3;
AdcRegs.ADCSOC1CTL.bit.CHSEL= 3;
AdcRegs.ADCSOC2CTL.bit.CHSEL= 4;
AdcRegs.ADCSOC3CTL.bit.CHSEL= 6;
AdcRegs.ADCSOC4CTL.bit.CHSEL= 2;
AdcRegs.ADCSOC5CTL.bit.CHSEL= 1;
AdcRegs.ADCSOC6CTL.bit.CHSEL= 0x0e;
AdcRegs.ADCSOC7CTL.bit.CHSEL= 0x00;
AdcRegs.ADCSOC8CTL.bit.CHSEL= 0x0d;
AdcRegs.ADCSOC9CTL.bit.CHSEL= 0x0f;
AdcRegs.ADCSOC10CTL.bit.CHSEL= 9;
AdcRegs.ADCSOC11CTL.bit.CHSEL= 7;

AdcRegs.ADCSOC12CTL.bit.CHSEL= 0x0b;
AdcRegs.ADCSOC13CTL.bit.CHSEL= 0;
AdcRegs.ADCSOC14CTL.bit.CHSEL= 8;
AdcRegs.ADCSOC15CTL.bit.CHSEL= 5;

AdcRegs.ADCSOC0CTL.bit.TRIGSEL = 5;
AdcRegs.ADCSOC1CTL.bit.TRIGSEL = 5;
AdcRegs.ADCSOC2CTL.bit.TRIGSEL = 5;
AdcRegs.ADCSOC3CTL.bit.TRIGSEL = 5;
AdcRegs.ADCSOC4CTL.bit.TRIGSEL = 5;
AdcRegs.ADCSOC5CTL.bit.TRIGSEL = 5;
AdcRegs.ADCSOC6CTL.bit.TRIGSEL = 5;
AdcRegs.ADCSOC7CTL.bit.TRIGSEL = 5;
AdcRegs.ADCSOC8CTL.bit.TRIGSEL = 5;
AdcRegs.ADCSOC9CTL.bit.TRIGSEL = 5;
AdcRegs.ADCSOC10CTL.bit.TRIGSEL = 5;
AdcRegs.ADCSOC11CTL.bit.TRIGSEL = 5;

AdcRegs.ADCSOC12CTL.bit.TRIGSEL = 0x0c;
AdcRegs.ADCSOC13CTL.bit.TRIGSEL = 0x0c;
AdcRegs.ADCSOC14CTL.bit.TRIGSEL = 0x0c;
AdcRegs.ADCSOC15CTL.bit.TRIGSEL = 5;

AdcRegs.ADCINTSOCSEL1.bit.SOC0 = 0;
AdcRegs.ADCINTSOCSEL1.bit.SOC1 = 0;
AdcRegs.ADCINTSOCSEL1.bit.SOC2 = 0;
AdcRegs.ADCINTSOCSEL1.bit.SOC3 = 0;
AdcRegs.ADCINTSOCSEL1.bit.SOC4 = 0;
AdcRegs.ADCINTSOCSEL1.bit.SOC5 = 0;
AdcRegs.ADCINTSOCSEL1.bit.SOC6 = 0;
AdcRegs.ADCINTSOCSEL1.bit.SOC7 = 0;
AdcRegs.ADCINTSOCSEL2.bit.SOC8 = 0;
AdcRegs.ADCINTSOCSEL2.bit.SOC9 = 0;
AdcRegs.ADCINTSOCSEL2.bit.SOC10 = 0;
AdcRegs.ADCINTSOCSEL2.bit.SOC11 = 0;
AdcRegs.ADCINTSOCSEL2.bit.SOC12 = 0;
AdcRegs.ADCINTSOCSEL2.bit.SOC13 = 0;
AdcRegs.ADCINTSOCSEL2.bit.SOC14 = 0;
AdcRegs.ADCINTSOCSEL2.bit.SOC15 = 0;

AdcRegs.ADCCTL1.bit.TEMPCONV = 1;

AdcRegs.INTSEL1N2.bit.INT1SEL = 3;
AdcRegs.INTSEL1N2.bit.INT1CONT = 0;
AdcRegs.INTSEL1N2.bit.INT1E = 1;

AdcRegs.INTSEL1N2.bit.INT2SEL = 13;
AdcRegs.INTSEL1N2.bit.INT2CONT = 0;
AdcRegs.INTSEL1N2.bit.INT2E = 1;

在一个字中、80引脚 F28034只有一个 ADC 模块有16个通道、而 ADC 只有16个 SOC 触发信号、所以如果设定下面的顺序或同步采样模式、如果应用程序调用一个指定的转换系列、SOC0→SOC1→SOC2、来定期启动。然后改为将系列设置为 SOC0→SOC1→SOC2→SOC3、并且仅使用最后三个转换、即 ADCRESULT1、ADCRESULT2、ADCRESULT3、从而丢弃 ADCRESULT0。因此、客户会浪费一些模拟渠道资源。您能否更详细地解释一下"ADC：初始转换"？或如何设计以满足客户对多达16通道 ADC 采样的需求。非常感谢！