各位大侠救命,遇到个问题:MSP430F5438A 进入LPM3后,在定时器中断中退出低功耗,无法进入主程序,然后就只能进入定时中断程序了,好像是退出不了低功耗模式。而且这种情况是偶然出现的。与变量太多有关吗?在初始化时在一个结构体前加了__no_init,不然初始化超时重启。
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各位大侠救命,遇到个问题:MSP430F5438A 进入LPM3后,在定时器中断中退出低功耗,无法进入主程序,然后就只能进入定时中断程序了,好像是退出不了低功耗模式。而且这种情况是偶然出现的。与变量太多有关吗?在初始化时在一个结构体前加了__no_init,不然初始化超时重启。
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//******************************************************************************
// MSP430x54x Demo - Enters LPM3 (ACLK = LFXT1)
//
// Description: Configure ACLK = LFXT1 and enters LPM3. Measure current.
// ACLK = LFXT1 = 32kHz, MCLK = SMCLK = default DCO
// Note: SVS(H,L) & SVM(H,L) not disabled
//
// MSP430x5438
// -----------------
// /|\ | XIN|-
// | | | 32kHz
// ---|RST XOUT|-
// | |
//
// W. Goh
// Texas Instruments Inc.
// April 2009
// Built with CCE Version: 3.2.2 and IAR Embedded Workbench Version: 4.11B
//******************************************************************************
#include <msp430.h>
int main(void)
{
WDTCTL = WDTPW+WDTHOLD; // Stop WDT
P7SEL |= 0x03; // Select XT1
UCSCTL6 &= ~(XT1OFF); // XT1 On
UCSCTL6 |= XCAP_3; // Internal load cap
// Loop until XT1,XT2 & DCO stabilizes
do
{
UCSCTL7 &= ~(XT2OFFG + XT1LFOFFG + XT1HFOFFG + DCOFFG);
// Clear XT2,XT1,DCO fault flags
SFRIFG1 &= ~OFIFG; // Clear fault flags
}while (SFRIFG1&OFIFG); // Test oscillator fault flag
UCSCTL6 &= ~(XT1DRIVE_3); // Xtal is now stable, reduce drive
// strength
P1OUT = 0x00;
P2OUT = 0x00;
P3OUT = 0x00;
P4OUT = 0x00;
P5OUT = 0x00;
P6OUT = 0x00;
P7OUT = 0x00;
P8OUT = 0x00;
P9OUT = 0x00;
P10OUT = 0x00;
P11OUT = 0x00;
PJOUT = 0x00;
P1DIR = 0xFF;
P2DIR = 0xFF;
P3DIR = 0xFF;
P4DIR = 0xFF;
P5DIR = 0xFF;
P6DIR = 0xFF;
P7DIR = 0xFF;
P8DIR = 0xFF;
P9DIR = 0xFF;
P10DIR = 0xFF;
P11DIR = 0xFF;
PJDIR = 0xFF;
__bis_SR_register(LPM3_bits); // Enter LPM3
//可以加个延时或者用外部中断打断一下试试
LPM3_EXIT;
}
void main(void)
{
......
__low_power_mode_3();
}
#pragma vector=TIMER0_A0_VECTOR
__interrupt void Timer_A (void)
{
TA0CCR0 =656;
if(...)
{
__low_power_mode_off_on_exit();
}
}
#pragma vector = PORT2_VECTOR
__interrupt void port2(void)
{
__low_power_mode_off_on_exit() ;
}
流程就是这样的,感谢