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DMA将ADC12的数据不能传到乘法器中？

qiang liu2
Intellectual 692 points


DMACTL0 =DMA0TSEL_24+DMA1TSEL_24;
DMACTL4 = DMARMWDIS;
__data16_write_addr((unsigned short) &DMA0SA,(unsigned long) &ADC12MEM0); //DMA0 目的地址
__data16_write_addr((unsigned short) &DMA0DA,(unsigned long) &MPY); //DMA0源地址
DMA0SZ=1; // DMA0 size = 1
DMA0CTL = DMADT_4+DMAEN+DMADSTBYTE+DMASRCBYTE; //


__data16_write_addr((unsigned short) &DMA1SA,(unsigned long) &ADC12MEM1); //DMA1 目的地址
__data16_write_addr((unsigned short) &DMA1DA,(unsigned long) &OP2); //DMA1源地址
DMA1SZ=1; // DMA1 size = 1
DMA1CTL = DMADT_4+DMAEN+DMADSTBYTE+DMASRCBYTE;

ADC12MEM0和ADC12MEM1中已经采集到了数据，但是DMA不能将数据传递到MPY和OP2中，MDA代码如上。

  • 0
    TI__Genius 12740 points

      // Setup DMA0
      DMACTL0 = DMA0TSEL_24;                    // ADC12IFGx triggered
      DMACTL4 = DMARMWDIS;                      // Read-modify-write disable
      DMA0CTL &= ~DMAIFG;
      DMA0CTL = DMADT_4+DMAEN+DMADSTINCR_3+DMAIE; // Rpt single tranfer, inc dst, Int
      DMA0SZ = 1;                               // DMA0 size = 1

      __data16_write_addr((unsigned short) &DMA0SA,(unsigned long) &ADC12MEM0);
                                                // Source block address
      __data16_write_addr((unsigned short) &DMA0DA,(unsigned long) &DMA_DST);
                                                // Destination single address

    参见这个例程，希望对你有所帮忙。

  • 0 回复 Maka Luo
    Intellectual 692 points

    你好！你说的这个代码我已经看过，但是有个问题：当我把ADC12的转换模式改为ADC12CONSEQ_2（单通道序列转换）就可以将ADC12MEN0的值转移到MPY中区，但是当我将ADC12转换模式改为ADC12CONSEQ_3（序列通道序列转换）时，DMA就不能将ADC12MEM0传到MPY，也不能将ADC12MEM1传到OP2中。不知道是什么原因？希望您能够再详细的讲解哈！谢谢！