msp430f2619 配置PWM波形问题

那，能让timer_a的比较的TA1触发中断，TA0输出PWM可以吗？在中断服务程序里面令P3.0的电平翻转？  我现在程序感觉没法触发中断，请各位帮我分析一下，哪里出了问题？

void main(void) {   int iq0=0;   WDTCTL = WDTPW + WDTHOLD;                 // Stop Watchdog Timer   BCSCTL1 &= ~XT2OFF;        //ACLK为XT1，开启XT2震荡  do      {           IFG1 &= ~OFIFG;                  //清除振荡器失效标志       

    for (iq0=0xFF; iq0>0; iq0--);    //延时，等待XT2起振      }     

      while ((IFG1 & OFIFG)!= 0);     //判断XT2是否起振  

BCSCTL2=SELM_2+SELS+DIVS_0+DIVM_0;               //选择MCLK、SMCLK为XT2 ,SMCLK 8分频  

 BCSCTL3=XCAP_1+LFXT1S_0+XT2S_2;    //XT1工作在32.768KHz的低频模式下，内部电容为6PF，XT2的频率为2-16MHZ

  P3DIR |= 0xff;   P3SEL=0x00;   P5DIR |= 0x78;                            // P5.6,5,4,3 outputs  

 P5SEL |= 0x70;                           // P5.6,5,4 options   P1DIR |= 0x0C;                            // P1.2 and P1.3 output  

 P1SEL |= 0x0C;                            // P1.2 and P1.3 TA1/2 options

   P2DIR|=0x80;                              // P2.7 output

   P2SEL=0x80;                               // P2.7 TA1/2 options  output=20khz,50%   P4DIR|=0x46;                             //P4.1 and P4.6 output   P4SEL=0x46;                             //P4.1TB1 and P4.6 TB7 options   

   CCR0 =124;                               // PWM Period/2             

 CCTL0=OUTMOD_4 +CCIE;                           //CCR0 toggle        

 TACTL = TASSEL_2 + MC_3+ID_0;                  // SMCLK, mode up/dowm  

while (1)                                 // 10 MCLK cycle loop  

 {     P5OUT |= 0x08;                          // P5.3 = 1     P5OUT &= ~0x08;                         // P5.3 = 0   } }

 #pragma vector=TIMERA0_VECTOR __interrupt

void Timer_A (void)

 {   P3OUT= 0x00;                        // Toggle P3.0 }