Thread 中讨论的其他器件:C2000WARE
工具与软件:
我打算使用 ADCA0~5 ADCB0~5、其中 SOC0被分配给 ADCA0、SOC1被分配给 ADCA1、...依顺序依此类推。
相关代码的设置如下
void setupADC(void) { //single ended AdcSetMode(ADC_ADCA, ADC_RESOLUTION_12BIT, ADC_SIGNALMODE_SINGLE); AdcSetMode(ADC_ADCB, ADC_RESOLUTION_12BIT, ADC_SIGNALMODE_SINGLE); EALLOW; //ADCA AdcaRegs.ADCCTL2.bit.PRESCALE = 0; AdcaRegs.ADCCTL1.bit.INTPULSEPOS = 1; AdcaRegs.ADCCTL1.bit.ADCPWDNZ = 1; //ADCB AdcbRegs.ADCCTL2.bit.PRESCALE = 0; AdcbRegs.ADCCTL1.bit.INTPULSEPOS = 1; AdcbRegs.ADCCTL1.bit.ADCPWDNZ = 1; EDIS; DELAY_US(1000); } void setupADCSOC(void) { EALLOW; //ADCA AdcaRegs.ADCSOC0CTL.bit.CHSEL = 0; // SOC0(=ADCA0) AdcaRegs.ADCSOC0CTL.bit.ACQPS = 50; AdcaRegs.ADCSOC0CTL.bit.TRIGSEL = 1; // Trigger on CPUTIMER0 AdcaRegs.ADCSOC1CTL.bit.CHSEL = 1; // SOC1(=ADCA1) AdcaRegs.ADCSOC1CTL.bit.ACQPS = 50; AdcaRegs.ADCSOC1CTL.bit.TRIGSEL = 1; // Trigger on CPUTIMER0 // AdcaRegs.ADCSOC2CTL.bit.CHSEL = 2; // SOC2(=ADCA2) AdcaRegs.ADCSOC2CTL.bit.ACQPS = 50; AdcaRegs.ADCSOC2CTL.bit.TRIGSEL = 1; // Trigger on CPUTIMER0 AdcaRegs.ADCSOC3CTL.bit.CHSEL = 3; // SOC3(=ADCA3) AdcaRegs.ADCSOC3CTL.bit.ACQPS = 50; AdcaRegs.ADCSOC3CTL.bit.TRIGSEL = 1; // Trigger on CPUTIMER0 AdcaRegs.ADCSOC4CTL.bit.CHSEL = 4; // SOC4(=ADCA4) AdcaRegs.ADCSOC4CTL.bit.ACQPS = 50; AdcaRegs.ADCSOC4CTL.bit.TRIGSEL = 1; // Trigger on CPUTIMER0 AdcaRegs.ADCSOC5CTL.bit.CHSEL = 5; // SOC5(=ADCA5) AdcaRegs.ADCSOC5CTL.bit.ACQPS = 50; AdcaRegs.ADCSOC5CTL.bit.TRIGSEL = 1; // Trigger on CPUTIMER0 // AdcaRegs.ADCINTSEL1N2.bit.INT1SEL = 0; // End of SOC5 will set INT1 flag // AdcaRegs.ADCINTSEL1N2.bit.INT1E = 1; // Enable INT1 flag // AdcaRegs.ADCINTFLGCLR.bit.ADCINT1 = 1; // Make sure INT1 flag is cleared //ADCB AdcbRegs.ADCSOC0CTL.bit.CHSEL = 0; // SOC0(=ADCB0) AdcbRegs.ADCSOC0CTL.bit.ACQPS = 50; AdcbRegs.ADCSOC0CTL.bit.TRIGSEL = 1; // Trigger on CPUTIMER0 AdcbRegs.ADCSOC1CTL.bit.CHSEL = 1; // SOC1(=ADCB1) AdcbRegs.ADCSOC1CTL.bit.ACQPS = 50; AdcbRegs.ADCSOC1CTL.bit.TRIGSEL = 1; // Trigger on CPUTIMER0 AdcbRegs.ADCSOC2CTL.bit.CHSEL = 2; // SOC2(=ADCB2) AdcbRegs.ADCSOC2CTL.bit.ACQPS = 50; AdcbRegs.ADCSOC2CTL.bit.TRIGSEL = 1; // Trigger on CPUTIMER0 AdcbRegs.ADCSOC3CTL.bit.CHSEL = 3; // SOC3(=ADCB3) AdcbRegs.ADCSOC3CTL.bit.ACQPS = 50; AdcbRegs.ADCSOC3CTL.bit.TRIGSEL = 1; // Trigger on CPUTIMER0 AdcbRegs.ADCSOC4CTL.bit.CHSEL = 4; // SOC4(=ADCB4) AdcbRegs.ADCSOC4CTL.bit.ACQPS = 50; AdcbRegs.ADCSOC4CTL.bit.TRIGSEL = 1; // Trigger on CPUTIMER0 AdcbRegs.ADCSOC5CTL.bit.CHSEL = 5; // SOC5(=ADCB5) AdcbRegs.ADCSOC5CTL.bit.ACQPS = 50; AdcbRegs.ADCSOC5CTL.bit.TRIGSEL = 1; // Trigger on CPUTIMER0 // AdcbRegs.ADCINTSEL1N2.bit.INT1SEL = 5; // End of SOC5 will set INT1 flag //AdcbRegs.ADCINTSEL1N2.bit.INT1E = 1; // Enable INT1 flag // AdcbRegs.ADCINTFLGCLR.bit.ADCINT1 = 1; // Make sure INT1 flag is cleared EDIS; }
正如预期的那样、当向 ADCA0引脚施加3.3V 电压时、RESULT0寄存器应输出4095、而 当向 ADCA0引脚施加0V 电压时、结果0应产生0。
但是、将3.3V 施加到 ADCA0会更改 RESULT1和 RESULT2寄存器中的值 (在这个情况下、引脚 ADCA1至 ADCA5被连接至 GND。)
此外、当向 ADCA1施加3.3V 电压(将 ADCA1和 ADCA 2至5连接至 GND)时、RESULT1寄存器的值没有变化。
我已正确分配引脚、将 SW2:基准电压设置为0–3.3V、但我仍然遇到结果寄存器值的意外变化以及 ADCB 中的同样问题。
--> ADCA0:0V
RESULT1、2 --> 0
和 adcA1 3.3V (黄线)-->所有结果0