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Multiple triggers as sources for the start-of-conversion (SOC) sequence– S/W - software immediate start– ePWM 1-6– GPIO XINT2
Why XINT1 can start ADC (SOC mode) ???
为啥XINT1也能触发启动ADC
原则上只有XINT2可以触发ADC转换，请问如何判断是XINT1触发的？
我通过仿真，看到进入ADC中断
#include "DSP28x_Project.h"
interrupt void adc_isr(void);interrupt void xint1_isr(void);
Uint16 Result = 0;
main(){ InitSysCtrl();
EALLOW; SysCtrlRegs.HISPCP.all = 3; EDIS;
DINT;
InitPieCtrl();
IER = 0x0000; IFR = 0x0000;
InitPieVectTable();
EALLOW; PieVectTable.ADCINT = &adc_isr; PieVectTable.XINT1 = &xint1_isr; EDIS;
InitAdc();
AdcRegs.ADCMAXCONV.all = 0x0000; AdcRegs.ADCCHSELSEQ1.bit.CONV00 = 0x0;// ADCINA0 AdcRegs.ADCTRL2.bit.EXT_SOC_SEQ1 = 1; AdcRegs.ADCTRL2.bit.INT_ENA_SEQ1 = 1;
EALLOW; GpioCtrlRegs.GPAMUX1.bit.GPIO0 = 0;// LED GpioCtrlRegs.GPADIR.bit.GPIO0 = 1; EDIS;
GpioDataRegs.GPASET.bit.GPIO0 = 1;
EALLOW; GpioCtrlRegs.GPAMUX1.bit.GPIO15 = 0;// XINT1 GpioCtrlRegs.GPADIR.bit.GPIO15 = 0; GpioCtrlRegs.GPAPUD.bit.GPIO15 = 1; GpioCtrlRegs.GPAQSEL1.bit.GPIO15 = 2; GpioCtrlRegs.GPACTRL.bit.QUALPRD1 = 0xFF; EDIS;
EALLOW; GpioIntRegs.GPIOXINT1SEL.bit.GPIOSEL = 15; EDIS;
XIntruptRegs.XINT1CR.bit.POLARITY = 1; XIntruptRegs.XINT1CR.bit.ENABLE = 1;
PieCtrlRegs.PIECTRL.bit.ENPIE = 1; PieCtrlRegs.PIEIER1.bit.INTx6 = 1; PieCtrlRegs.PIEIER1.bit.INTx4 = 1; IER |= M_INT1; EINT;
for(;;);}
interrupt void adc_isr(void){ Result = AdcRegs.ADCRESULT0 >>4;
AdcRegs.ADCTRL2.bit.RST_SEQ1 = 1; AdcRegs.ADCST.bit.INT_SEQ1_CLR = 1; PieCtrlRegs.PIEACK.all = PIEACK_GROUP1;}
interrupt void xint1_isr(void){ GpioDataRegs.GPATOGGLE.bit.GPIO0 = 1;
PieCtrlRegs.PIEACK.all = PIEACK_GROUP1;}
我已经把程序粘贴到论坛
